[~] = divide bye!

[x] = times bye!

ILLUSION 1: Venus (diameter) 12,103.6 km ~ Moon (diameter) 3476 km = 3.4820 times larger then Moon, for Venus to look the same size of the Sun as the Moon does from Earth, we would have to calculate the distance of the Moon from the Earth and multiply it 3.4820 times.

Venus is 3.4820 times larger then the Moon, therefore, a distance 3.4820 times away from Earth is needed to create the same optical illusion the Moon does with the Sun.

Moon distance from Earth: 384,400 km x 3.4820 = 1,338,480.8 km.

Venus would have to be 1,338,480.8 kilometers away from Earth to look the same size of the Sun as the Moon does from Earth. And since the Earth is 149,600,000 km away from the Sun, Venus would have to orbit at 148,261,519.2 from the Sun.

[149,600,000] - [1,338,480.8] = 148,261,519.2 km.

Science-fiction tells us that Venus occupies the 108,200,000 km position from the Sun, a (difference) of 40,061,519.2 km from Earth, if we take the (hypothetical orbit) of where Venus would appear to have the same size of the Sun from Earth (1,338,480.8 km) and divide it with the (difference) we'd have an approximate of what Venus really looks like in size when viewed from Earth compared to the Sun in her original orbit.

40,061,519.2 (divided) by 1,338,480.8 = 29.93

Venus in her original orbital position loses 30% the size of the Sun as it appears on Earth in our skies.

The Scientistic Radicals will argue that Venus fits 114.84 times along the Sun’s diameter and that to cover the whole surface disk area of the Sun you would need 13,189 images of Venus, this is incorrectly false, here is the proof of that confusing and deceptive scientific lie.

If you would for a moment consider Venus in her hypothetical orbit around Earth where she creates the optical illusion of being the same size as the Sun appears in our skies, Venus at this orbit would appear 100% the same size of the Sun, would fill in all the imaginary 13,189 surface area disk of the Sun. When Venus reassumes her original orbit a certain percentage of that optic, a certain amount of those imaginary surface area disk slots are lost. Lets calculate what percentage and how many surface area disk slots Venus retains in her 108,200,000 km position from the Sun.

ILLUSION 2: On the percentage scale starting at (zero) being the Sun, Venus is 1/13,189 the size of the Sun and all the way-out to her hypothetical orbit of (148,261,519.2) being a 100 percent of the Sun’s size as seen on Earth. When resuming to her original orbit at 108,200,000 km Venus would lose a certain percentage of that optic when viewed from Earth, to calculate that lose we’ll put the hypothetical orbit on a percentage scale and divide into her original position from the Sun.

108,200,000 km ~ 148,261,519.2 km = 72.97% Venus RETAINS in size compared to our Sun as it appears like in our skies. OPTICS

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ILLUSION 3: On the imaginary surface area disk scale Venus is 1/13,189 the size of the Sun and when in her hypothetical orbit (148,261,519.2) Venus covers all the imaginary 13,189 [V] slots, when resuming to her original orbit at 108,200,000 km again a certain amount of these “slots” are lost. Lets calculate how many slots Venus retains when resuming her original position.

13,189 (slots) ~ 148,261,519.2 (km) = 0.000088957 slots per kilometer.

0.000088957 x 108,200,000 (km) = 9,625.1474 slots/13,189

9,622 ~ 13,189 = (72.97%)

When viewing the planet named Venus (optically) she would have the appearance of almost 3/4 the size of our Sun as seen in OUR sky.

Whatever ILLUSION you choose, remember that GOD’S light shines for everyone, this is my ILLUSION of Venus.

http://img114.imageshack.us/img114/263/mycollagezi2.jpg

Regards,

The Punisher.