//edited some errors, G is not /~ r^2 sorry. Was thinking of declining of force

As you might understand, a force needs a vektor, since forces release energy, and for a photon to be released, there must allready be an existing vektor along a coordinate which change direction into the room or, if mechanical force, remains in the room.

But in a black hole, no vektor can exist since acceleration is as good as total and any vektor would be severely slowed down in a black hole. But it still has gravity which leads to the conclusion that gravity is caused by an outer force, an "empty" spacetime force.

This is the first idea: The EM force would be caused by that the vector along time has two directions and light speed. The lightspeed would cause the time coordinate to be infinitely thin, and hence, the illusion is that the vektors are not moving away from eachother along this coordinate, and in their comparative system, they are not. Hence positive and negative particles have opposit vektors, and when colliding, they change directions into the room in the form of photons.

This is the second idea:

The cosmological constant applies to time distance aswell, and it is attracting along the imaginary time coordinate. Even if time in our RF is infinitely thin, it still has a distance. But the force caused by the distance, only declines from the time vector throughout the room, and it is not only proportional to the time past, it is directly additive and by that I mean that it stacks as if the vektor have not moved but the distance have increased.

Equations:

v = everage time speed

G ~ vt/4pi

/4pi for the sperical decline

(1.)But since all energy is equally effected by this force, and all vektors in space slows down caused by force (and just like black holes slows down in timevektor), G is also /~ with vt since force is ~ vektor.

G ~ 1/4pi

Also, one must add, that the constant would be proportional to the mass area A, since the bend in spacetime is caused by the tunnel it makes in 4d. For a 2d surface with a tunnel along the third dimension, the force is caused by the tunnel circle as compared to the circle it declines with. Circle against circle, surface against surface.

G ~ A/4pi

I don't know if there are any more proportionalities. If you see something more just pm me, until further notice:

G = A/4pi = (A(m)/m)/4pi

Note: the energydensity is both ~ and /~ by reasons mentioned (1.)

Thank you for reading this far.

Yep, that should definitely describe it:

F = (A(m)/m)*m(1)*m(2)/(r^2*4pi)

One kilo mass, 8.38502389 E-10 m^2 surface.Can it be possible?

surface ~ mass. Look, surface is proportional to mass. Else A(m)/m would not be constant.

If vectors shortens, so does the force!