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Thread: Synchronizing clocks on inertial frames by measuring absolute motion.

  1. #1 Synchronizing clocks on inertial frames by measuring absolute motion. 
    Forum Freshman geistkiesel's Avatar
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    Transponders A and Bare separated by a constant distance. Light pulses emitted from A toward B reflectback to A from B. The transponders measure and log these events of emission and absorption time events into the system data base when the events occur.
    Equivalent times on A and B transponder clocks are entered on same level in the table when occurring.


    A B Data Collected & recorded
    A0 Bu Unknown
    A0 + B1 Bu + B1 Total known
    A2 Bu + A2 = x2 measured
    A2 + B1 Bu + A2 + B1 = x2 measured
    X2 - X1 = Bu + A2 + B1 – (Bu + A2) = B1






    A0___________________________|B1
    ----------- A
    2|__________________|



    1. The pulse leaves A at A0 when the Bclock time-of-day is unknown, Bu.
    2. The pulse arrives at B at the clock time is Bu+ B1 where this total is known and recorded and when the A clock is A0+ B1 alsoan unknown total.
    3. The pulse returns to A at A2 when the B clock is Bu +A2
    4. The pulse immediately is emitted and arrives atB at Bu + A2+ B1when the A clock is A2+ B1

    The B clock in the 3rd and 4th rows hasrecorded the total amounts listed and subtracting X2 - X1produces an unambiguous value B1 now used as the synchronous valueof the measurement.

    The out bound leg= d1 = B1– A0 and the inbound leg is d2 = A2 - B1
    d1 - d2= 2B1 – (A2 - A0). This difference of the twolegs is the distance of the round trip of light travels during the measured roundtrip time of the light pulse, which is related to the distance the A and Btransducers moved during the same time span. Therefore, Subtractingd1- d2 = D21 = VΔtn where n = 2,1.

    Theis value is V(A2 - A0) 1,2=[2B1 – (A2– A0)]
    Thus V =[2B1 – (A2 – A0)]/ (A2 - A0)
    And for A0 = 0
    V = 2B1/ A2 – 1.
    V is the absolute and measured velocity of the inertial frames A and B thatthe postulate of special relativity says is impossibility.

    Now what do we do? This scheme used only four independent time event meaqsurements


    Mother Nature include time in her creation so everything wouldn't happen all at once. Anon
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  3. #2  
    Quagma SpeedFreek's Avatar
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    This makes no sense to me, as you explained it.

    If "Transponders A and B are separated by a constant distance" then they are at rest in relation to each other, are they not?

    Where are you measuring V from?


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    [QUOTE=geistkiesel;282769]Transponders A and Bare separated by a constant distance. Light pulses emitted from A toward B reflectback to A from B. The transponders measure and log these events of emission and absorption time events into the system data base when the events occur.Equivalent times on A and B transponder clocks are entered on same level in the table when occurring. ........ You are stating indirectly that the space in which A and B are imbeded ( existing ) is totally void of motion hence Not interfeering with the light transmission ( in an absolute , yet measurable way ) .We know of the Cosmic Background Radiation proving that the `space`is in perpetual micro motion ( including the space in your experiment ) hence you need to adjust your calculations for it .Hey SpeedFreek , any comments É ( Question Mark ) Cheers ÉÉÉ
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