E = mc2 = m(c/cos0)2

By Suhail Jalbout

Nothing can travel faster than the speed of light; the Theory of Relativity tells us. I think that it is possible for a single pulse of light energy, transmitted at random, to do just that if projected on an incline. The speed of each projected pulse will travel faster than the speed of light. I am not certain whether my analysis is purely a mathematical exercise or whether it has important theoretical and practical implications. I leave this in the hands of the experts.

Here are the equations that support my theory.

A. SPEED

Let c = the speed of the light energy pulse from the source (the speed of light)

V = the speed of the projected pulse on the incline

Ø = the angle between the direction of propagation of the pulse from the source and the incline

Then, the speed of the projected pulse is: V = c / cos Ø ………………equation (1)

When Ø approaches 0°, cos Ø = 1 and when Ø approaches 90°, cos Ø = 0.

Substituting these numbers in equation (1) gives:

cos Ø = 1 , V = c

cos Ø = 0 , V = ∞

B. ENERGY

The energy of the projected pulse is:

E = mV2 = m(c/cosØ)2

cos Ø = 1 , E = mc2

cos Ø = 0 , E = ∞

C. SPECIAL RELATIVITY EQUATIONS

cos Ø = 1 and speed c, Time Dilation = T = t₀ x 0 = 0

cos Ø = 0 and speed ∞, “Time Dilation” = T = t₀

cos Ø = 1 and speed c, Length Contraction = L = l₀ x 0 = 0

cos Ø = 0 and speed ∞, “Length Contraction” = L = l₀

cos Ø = 1 and speed c, Relativistic Mass = M = m₀ x ∞ = ∞

cos Ø = 0 and speed ∞, “Relativistic Mass” = M = m₀

In conclusion, there are two special cases relevant to the change in the values of angle Ø from 0° to 90° :

a. If Ø approaches 0°, cos Ø = 1 : the speed of propagation is equal to the speed of light and nothing will travel faster than this speed.

b. If Ø approaches 90°, cos Ø = 0 : the speed of propagation is infinite and travel is instantaneous without any changes to the steady state conditions of time, length and mass.