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Thread: Look at the diagram (? problem)

  1. #1 Look at the diagram (? problem) 
    Forum Freshman lanalang's Avatar
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    http://img205.imageshack.us/img205/3...diagramaw3.jpg

    The resistors in the parallel branch are 8.0? each

    a. what is the total resistance of the circuit?
    b. what is the power used by each resistance in the circuit?


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  3. #2  
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    Gosh, this isn't so hard. As Groucho once said, "It's so simple a child could do it. Someone fetch me a child!"

    Lanalang, you post your answer. We'll tell you if you're right.


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  4. #3  
    Forum Freshman lanalang's Avatar
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    well i didn't know how to do this at the first place so i didn't know the answer thats why i asked you guys
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  5. #4  
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    Then we'll walk you through it.

    First, throw out R1 and R2. Ignore the 120v source as well. All you have left are the two 8 ohm resistors in parallel. Now what is the combined resistance of these two 8 ohm parallel resistors?
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  6. #5  
    Forum Freshman lanalang's Avatar
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    Quote Originally Posted by SteveF
    Then we'll walk you through it.

    First, throw out R1 and R2. Ignore the 120v source as well. All you have left are the two 8 ohm resistors in parallel. Now what is the combined resistance of these two 8 ohm parallel resistors?
    8 and 8 combined will make it 64 i guess
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  7. #6  
    Forum Masters Degree bit4bit's Avatar
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    No, 1/ R_total = 1/ R_1 + 1/ R_2 for resistors in parallel...
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  8. #7  
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    Or,
    R(parallel)=R1R2/(R1+R2)
    Here R1 and R2 are the two parallel resistors, not the ones labeled R1 and R2 in your diagram. Hope that's not too confusing.

    Do you have a textbook, and doesn't it have a formula like that?
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