# Thread: electrostatic question

1. The equation you use to solve the magnitude of the electric field at a point between two oppositely charged plates is qE=F right? Because I tried that and I did not get the answer. Heres the question. The two oppositely charged plates are 5.00mm apart and the point P is 2.00mm from the positively charged plate. If the potential difference between them is 450V, what is the magnitude of the electric field at point P?

Any help would be greatly appreciated.

Thanks  2.

3. Originally Posted by FancyShoes
The equation you use to solve the magnitude of the electric field at a point between two oppositely charged plates is qE=F right? Because I tried that and I did not get the answer. Heres the question. The two oppositely charged plates are 5.00mm apart and the point P is 2.00mm from the positively charged plate. If the potential difference between them is 450V, what is the magnitude of the electric field at point P?

Any help would be greatly appreciated.

Thanks
The equation you listed gives the force F on a charge q within an electrical field E. The formula you need is the one that gives the electrical field E between the plates of a capacitor as a function of the distance d between the plates and the voltage V. The location of point P isn't going to matter because the electric field in a capacitor is constant.  Bookmarks
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