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Thread: Finding the x and y components

  1. #1 Finding the x and y components 
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    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.


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  3. #2  
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    Show us how you got 64.30 and -2.59.


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  4. #3  
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    Quote Originally Posted by nerdhere View Post
    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.
    You know that

    You also know that , ........
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  5. #4  
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    Thank you for replying!

    Anyway, what I did first was a graph on how the forces actually looked like. Then I set out table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    Actually, I have an illustration of the graph, however uploading failed. So I guess the table will be a great help. Thanks.
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  6. #5  
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    Quote Originally Posted by xyzt View Post
    Quote Originally Posted by nerdhere View Post
    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.
    You know that

    You also know that , ........
    Thank you for replying!

    Yup, I know what you're talking about. In our quiz, everything I did was correct except for the table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    I really thought I was on the right track because I just followed what I've learned from class. Then when the answers came out, I was in total shock because I couldn't find the error/s in my table. So can you please help me? Thank you.
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  7. #6  
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    Quote Originally Posted by Harold14370 View Post
    Show us how you got 64.30 and -2.59.
    Thank you for replying!

    Anyway, what I did first was a graph on how the forces actually looked like. Then I set out table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    Actually, I have an illustration of the graph, however uploading failed. So I guess the table will be a great help. Thanks.
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  8. #7  
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    Quote Originally Posted by nerdhere View Post
    Quote Originally Posted by xyzt View Post
    Quote Originally Posted by nerdhere View Post
    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.
    You know that

    You also know that , ........
    Thank you for replying!

    Yup, I know what you're talking about. In our quiz, everything I did was correct except for the table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    I really thought I was on the right track because I just followed what I've learned from class. Then when the answers came out, I was in total shock because I couldn't find the error/s in my table. So can you please help me? Thank you.

    You did things right except you made a fatal error for Force C components: force C has a magnitude of 50 lb and directed southward;



    When you put this into the summation, you get the correct results. You are off by 50 in the x direction (and by -50 in the y direction). I feel bad for you.
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  9. #8  
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    As xyzt pointed out, C is wrong. South (in this notatation) is -90.
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  10. #9  
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    Quote Originally Posted by nerdhere View Post
    Quote Originally Posted by xyzt View Post
    Quote Originally Posted by nerdhere View Post
    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.
    You know that

    You also know that , ........
    Thank you for replying!

    Yup, I know what you're talking about. In our quiz, everything I did was correct except for the table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    I really thought I was on the right track because I just followed what I've learned from class. Then when the answers came out, I was in total shock because I couldn't find the error/s in my table. So can you please help me? Thank you.
    BTW, you are welcome!
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  11. #10  
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    Quote Originally Posted by xyzt View Post
    Quote Originally Posted by nerdhere View Post
    Quote Originally Posted by xyzt View Post
    Quote Originally Posted by nerdhere View Post
    Hi. I really need help for this problem:

    Four forces act concurrently at one point. Force A has a magnitude of 70 lb and is directed 30 degrees North of East; force B has a magnitude of 60 lb and is directed westward; force C has a magnitude of 50 lb and directed southward; and force D has a magnitude of 40 lb and direction 20 degrees measured in the sense from the negative y-axis toward the positive x-axis. What are the x and y components of the resultant of the four forces?

    It was given as a quiz during our summer classes and I failed to answer it. My x-component was 64.30 and my y-component was -2.59. However the correct answers were 14.30 for the x-component and -52.59 for the y-component.

    Thank you in advance.
    You know that

    You also know that , ........
    Thank you for replying!

    Yup, I know what you're talking about. In our quiz, everything I did was correct except for the table of values.

    *Table of Values*

    Force -> x-component -> y-component
    A 70cos30 70sin30
    B -60cos0 60sin0
    C 50cos0 -50sin0
    D 40sin20 -40cos20

    Therefore, the summation of x is 64.30 and y is -2.59.

    I really thought I was on the right track because I just followed what I've learned from class. Then when the answers came out, I was in total shock because I couldn't find the error/s in my table. So can you please help me? Thank you.

    You did things right except you made a fatal error for Force C components: force C has a magnitude of 50 lb and directed southward;



    When you put this into the summation, you get the correct results. You are off by 50 in the x direction (and by -50 in the y direction). I feel bad for you.
    Goodness! Thank you very much! I really am careless. I forgot that C is directed southward. I should have reviewed my answers before handling the paper. Yikes! Thank you again.
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  12. #11  
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    Quote Originally Posted by mathman View Post
    As xyzt pointed out, C is wrong. South (in this notatation) is -90.
    Thank you for your time! I really overlooked C.
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