# Thread: Calculation of curie constant

1. 1)The curie temperature of iron is 1043 Kelvin. Assume that iron atoms, when in metallic form have moments of 2 Bohr magneton per atom. Iron is body centered cube with lattice parameter a = 0.286 nm. Calculate the curie constant.
I solved it in the following way:
Let m be the magnetic moment of an iron atom, N be the number of atoms per unit volume, K be the boltzmann constant, mu be the permeability of free space and C be the Curie constant.
m = 2[m(B)] {where m(B) is Bohr magneton}
= 18.54 x 10^(-24) A-m^2
N = n/(a^3) {where n is number of atoms in 1 cubic lattice of iron}
= 2/[(0.286 x 10^(-9))^3]
= 8.5 x 10^28 atoms per unit volume
C = [(m^2)(mu)N]/[3K]
C = 0.89
But the answer given in my book is 0.66.  2.

3. Jesus CHRIST! what the hell are you talking about ?  4. its mathematical calculations to calculate a constant. this isnt that hard.  5. Originally Posted by Zelos
its mathematical calculations to calculate a constant. this isnt that hard.
I Agree.Now, would u mind telling whether it is right or not?  6. 1 cubic lattice of iron
sorry i cant help you since i am unfamiliar with the word lattice  7. Originally Posted by leohopkins
Jesus CHRIST! what the hell are you talking about ?
If you are to lazy to look it up, it the temperature at which magnetic domains lose their alignment, or if you like heat up a magnet it loses it's magnetism, but when it cools down again it recovers it.  Bookmarks
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