# Calculation of curie constant

• January 26th, 2007, 06:06 AM
Photon
Calculation of curie constant
1)The curie temperature of iron is 1043 Kelvin. Assume that iron atoms, when in metallic form have moments of 2 Bohr magneton per atom. Iron is body centered cube with lattice parameter a = 0.286 nm. Calculate the curie constant.
I solved it in the following way:
Let m be the magnetic moment of an iron atom, N be the number of atoms per unit volume, K be the boltzmann constant, mu be the permeability of free space and C be the Curie constant.
m = 2[m(B)] {where m(B) is Bohr magneton}
= 18.54 x 10^(-24) A-m^2
N = n/(a^3) {where n is number of atoms in 1 cubic lattice of iron}
= 2/[(0.286 x 10^(-9))^3]
= 8.5 x 10^28 atoms per unit volume
C = [(m^2)(mu)N]/[3K]
C = 0.89
But the answer given in my book is 0.66.
• January 26th, 2007, 06:15 AM
leohopkins
erm
Jesus CHRIST! what the hell are you talking about ?
• January 26th, 2007, 08:05 AM
Zelos
its mathematical calculations to calculate a constant. this isnt that hard.
• January 26th, 2007, 09:26 AM
Photon
Quote:

Originally Posted by Zelos
its mathematical calculations to calculate a constant. this isnt that hard.

I Agree.Now, would u mind telling whether it is right or not?
• January 26th, 2007, 09:40 AM
Zelos
Quote:

1 cubic lattice of iron
sorry i cant help you since i am unfamiliar with the word lattice
• January 26th, 2007, 11:45 AM
Re: erm
Quote:

Originally Posted by leohopkins
Jesus CHRIST! what the hell are you talking about ?

If you are to lazy to look it up, it the temperature at which magnetic domains lose their alignment, or if you like heat up a magnet it loses it's magnetism, but when it cools down again it recovers it.