Originally Posted by

**fred91**
Yes, you should use meters to avoid getting confused (you should also obtain the correct value of G in this system).

Sun mass is, anyway, approximately 2*10^30 kg.

What you've written about the orbit is the perihelion (for what I see in Wikipedia). The mean distance (think it is a mean) is 5.8*10^7 km

This gives a value of g = 5.95*10^8 G, if I'm not wrong, which is equal to g = 0.04 m/s^2

The one of the Earth, is 0.006 m/s^2, and it's a order of magnitude less because it is farther than Mercury, why does it seem too much to you?

Thanks for the Help.

Damn Big Values - I will just have to live with it.

I know - it LOOKS Big - because the Value is G is so Tiny - G = 6.67384 x 10^-11.

My problem - but this is the Third Time I have had to change the Calculations - and thus the Rules, in the last Two Years.

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I also had to make a Powers of 10 Correction to my Spreadsheet.

The Mass

**given** for the Sun / r^2 ( where r = 5.791 x 10^7 / 2 )

Using Sun Mass = 1.9881 x 10^30

These are Units of Kg and Km.

NOTE - 1.9891 x 10^30 is the value for Sun Mass in Kg - from Wiki.

So - Agreed - I need to Correct for Km to K.

As the Radius, in Km is "on the bottom" and Squared - the Value for the Result needs to be Corrected by 1 / 1 x 10^6.

HOWEVER - This gives a Value of 5.931 x 10^9 x G.

To get your given Answer of "near to" 5.95 x 10^8 - I have to make it 10 times SMALLER.

This gives me a Value of 5.931 x 10^9 x G.

COMMENTS ??