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Thread: Transverse doppler equation.

  1. #1 Transverse doppler equation. 
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    Just wanna clarify some equations.

    Transverse Doppler Effect

    In the formula provided, what does θ represent?


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    Quote Originally Posted by Naggy Doggy View Post
    Just wanna clarify some equations.

    Transverse Doppler Effect

    In the formula provided, what does θ represent?
    It is the angle between the relative velocity vector, and an imaginary line connecting the source and the observer of the wave signal. Refer also here :

    Relativistic Doppler effect - Wikipedia, the free encyclopedia


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    Quote Originally Posted by Markus Hanke View Post
    Quote Originally Posted by Naggy Doggy View Post
    Just wanna clarify some equations.

    Transverse Doppler Effect

    In the formula provided, what does θ represent?
    It is the angle between the relative velocity vector, and an imaginary line connecting the source and the observer of the wave signal. Refer also here :

    Relativistic Doppler effect - Wikipedia, the free encyclopedia
    So relative velocity vector refers to the relative velocity between the light source and the light detector?
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    Quote Originally Posted by Naggy Doggy View Post
    So relative velocity vector refers to the relative velocity between the light source and the light detector?
    Yes, between emitter and observer of the light.
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    ok thanks
    LOLDOG
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    Quote Originally Posted by Markus Hanke View Post
    Quote Originally Posted by Naggy Doggy View Post
    Just wanna clarify some equations.

    Transverse Doppler Effect

    In the formula provided, what does θ represent?
    It is the angle between the relative velocity vector, and an imaginary line connecting the source and the observer of the wave signal. Refer also here :

    Relativistic Doppler effect - Wikipedia, the free encyclopedia
    Hmm, this doesn't seem to be quite right, the definition is slightly different:


    "In the frame of the receiver, represents the angle between the direction of the emitter at emission (in other words, the relative velocity vector), and the observed direction of the light at reception (in other words, the wave vector of the light signal)."
    In the case of the TDE,
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    Quote Originally Posted by xyzt View Post

    Hmm, this doesn't seem to be quite right, the definition is slightly different:


    "In the frame of the receiver, represents the angle between the direction of the emitter at emission (in other words, the relative velocity vector), and the observed direction of the light at reception (in other words, the wave vector of the light signal)."
    In the case of the TDE,
    Maybe I am blind, but I fail to see the difference...?
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    Quote Originally Posted by Markus Hanke View Post
    Quote Originally Posted by xyzt View Post

    Hmm, this doesn't seem to be quite right, the definition is slightly different:


    "In the frame of the receiver, represents the angle between the direction of the emitter at emission (in other words, the relative velocity vector), and the observed direction of the light at reception (in other words, the wave vector of the light signal)."
    In the case of the TDE,
    Maybe I am blind, but I fail to see the difference...?
    Not the " imaginary line connecting the source and the observer" but the wave vector.
    It is the angle made by 2 vectors.
    Last edited by Howard Roark; April 1st, 2013 at 09:27 AM.
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  10. #9  
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    Quote Originally Posted by xyzt View Post
    Not the " imaginary line connecting the source and the observer" but the wave vector.
    It is the angle made by 2 vectors.
    Ok, I take your point, but then again, my "imaginary line" ( yeah, the expression is admittedly a bit silly ) would coincide with the direction of the wave vector...
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    Quote Originally Posted by Markus Hanke View Post
    Quote Originally Posted by xyzt View Post
    Not the " imaginary line connecting the source and the observer" but the wave vector.
    It is the angle made by 2 vectors.
    Ok, I take your point, but then again, my "imaginary line" ( yeah, the expression is admittedly a bit silly ) would coincide with the direction of the wave vector...
    Not really, the "imaginary line connecting the observer and the source" does not necessarily coincide with the wave vector.
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