Since I joined this forum I've been asking stupid questions. This is another one :

We are all familiar with this: s=vt+(at^2)/2

Now if the initial velocity, the acceleration, and the displacement are known, the time taken can be calculated through this:

t = [-v(+-)sqrt(v^2+2as)]/a ( note: +- means plus or minus )

Now we have two values of t!

I wanted to know what this would look like in the v-t diagram but never got around to it.

Please help explain this!