# Thread: Easy Physics Problem. Need Hints.

1. Alright, I'm in grade 11 and this is a homework problem but I don't want the answers to it, I need some hints as to how to do it.

Alright so first it say's:

a)What is the resistance of a coffee maker that draws a current of 5.0A from a 117V source?

So I found the answer to part A which is 23.4. But I'm stuck on part B here it is:

b)What resistance would have to be added in parallel with the same coffee maker to increase the current to 15.0A?

Please, If anyone can give me some hints that would be great. I know it is very easy, but I'm still stuck on it.  2.

3. What resistence would be needed to draw 10A?  4. I'm not sure if this is correct but, do I do it like this?

R = V/I so using the V from the previous question, 117V, and I, 10A, as you said that would be:

R = 117/10

= 11.7

So 11.7 of resistance is needed to draw 10A, or am I doing this all wrong?  5. good. now you should be able to find the solution.  6. This will be useful. For resistors in parallel, the equivalent resistance is: The numbers after each R function as numbering the resistors; they are not multipliers. So, n would be the nth resistor.  Bookmarks
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