1. 1,000 Liters of water contains 12 % of Salt , if the water is reduced to 600 liters it contains X % of salt find X.

I know the answer of this question but one of the step confuse me , it was 1,000X12/100 = 120 . But I can not find the unit for 120.

Its ok for water , had it been milk in place of water I wound not be able to solve it.

2.

3. If it had been milk, than you'd have to look at the density of milk. The unit is, of course,

4. If the 12% means 12% by volume, and if the volume of salt water is equal to the sum of the volume of the water and salt separately before they were mixed, which I do not know to be the case, then the number 120 you have calculated would be in liters of salt.

5. I want the answer if in place of water it was milk.

6. Originally Posted by Kalpit Darbhe
1,000 Liters of water contains 12 % of Salt , if the water is reduced to 600 liters it contains X % of salt find X.

I know the answer of this question but one of the step confuse me , it was 1,000X12/100 = 120 . But I can not find the unit for 120.

Its ok for water , had it been milk in place of water I wound not be able to solve it.
Do you mean 1,000 liters of salt and water mixture or do you mean 1,000 liters of water to which salt has been added?

If the water is reduced to 600 by pouring some away, X = 12%.

7. Seeing this as a percentage solution problem allows you to compute the answers.

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