# Thread: Resonance frequency

1. Hi!
Let's consider two similar guitar strings, one which is placed in a guitar and one placed "freely". If we snap the two strings in the same way, we will hear much stronger sound from the guitar than from the "freely" placed string. Now, I understand that this is due to resonance, but where does the additional energy actually come from? If we snap the strings in the same way, we have made an eauql "input" of energy to each string.

2.

3. True, but in the first case more of the energy is converted into sound, while in the second more energy is converted to kinetic energy. Unless I misunderstood 'freely'? (Mind you, this really isn't my area of expertise, so feel free to correct me if I'm wrong.)

4. Originally Posted by thyristor
Hi!
Let's consider two similar guitar strings, one which is placed in a guitar and one placed "freely". If we snap the two strings in the same way, we will hear much stronger sound from the guitar than from the "freely" placed string. Now, I understand that this is due to resonance, but where does the additional energy actually come from? If we snap the strings in the same way, we have made an eauql "input" of energy to each string.
It is a matter of local intensity not total energy. The energy input to the strings is the same and all of that energy is eventually converted into sound energy plus a little heat in the strings due to internal friction.

But the body of the guitar creates a resonance that results in a local amplification of the sound waves -- basically keeps some of the sound from dispersing as quickly.

5. what happens is that with the free string only maybe about 25% of the sound is actually going to your ears and with the string in the giutar the chamber behind the giuter (and the fact thate there is wood right behind the string) this materiel reflects the sound waves made back out making more of them stike your ear.

6. The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.

7. Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish

8. Originally Posted by DrRocket
Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish
Wrong!

9. Originally Posted by Twit of wit
Originally Posted by DrRocket
Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish
Wrong!
\

hardly

10. Originally Posted by DrRocket
Originally Posted by Twit of wit
Originally Posted by DrRocket
Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish
Wrong!
\

hardly
The string is vibrating, but moves little air, as it is too thin. The body has a large surface, so it can move move much more air.
http://www.phys.unsw.edu.au/~jw/guitarintro.html

11. Originally Posted by Twit of wit
Originally Posted by DrRocket
Originally Posted by Twit of wit
Originally Posted by DrRocket
Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish
Wrong!
\

hardly
The string is vibrating, but moves little air, as it is too thin. The body has a large surface, so it can move move much more air.
http://www.phys.unsw.edu.au/~jw/guitarintro.html
Don't believe everything that you read on the internet.

12. Originally Posted by DrRocket

Don't believe everything that you read on the internet.
I don't but this makes perfect sense.

13. Originally Posted by DrRocket
Originally Posted by thyristor
Hi!
Let's consider two similar guitar strings, one which is placed in a guitar and one placed "freely". If we snap the two strings in the same way, we will hear much stronger sound from the guitar than from the "freely" placed string. Now, I understand that this is due to resonance, but where does the additional energy actually come from? If we snap the strings in the same way, we have made an eauql "input" of energy to each string.
It is a matter of local intensity not total energy. The energy input to the strings is the same and all of that energy is eventually converted into sound energy plus a little heat in the strings due to internal friction.

But the body of the guitar creates a resonance that results in a local amplification of the sound waves -- basically keeps some of the sound from dispersing as quickly.
Wrong. Resonance starts and stops with the guitar string. We cannot presume that the body of the guitar is resonant to all of the sounds produced within the guitar. Competent technical discussion becomes further distressed by implication that sound wave amplification is accomplished without provision of a power supply.

It is simply that more sound energy is distributed into the air when more of the energy has been converted into such form.

14. Originally Posted by DrRocket
Originally Posted by dalemiller
The free string doesn't get a hold of as much air as the guitar surfaces provide in order to apply vibrational motion to launch air-born sound.
gibberish
It does not seem constructive, scientific, or within the normal constraints of decency to counter someone's statement with nothing but a malicious slur. Is the man jealous?

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