Hi,

i am having a little trouble with the Kirchhoff rule.

the loop rule says that around any closed loop in a circuit the sum of the potential rises (from a battery e.g.) must equql the sum of the potential drops (e.g. resistor).

Ohms law goes: V=I*R

so lets say we have a 6Volt battery, and a 4 Ohm resistor, then that would be

6/4 amps = I

but assuming there is no resistor then we would have

6V = I * 0 (???) what is the current (I)? where is the potential drop that equqls the 6V rise?

can anybody help me before the black hole will eat us on wednesday

thanks