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Thread: Discovery (5) / STC Analysis

  1. #1 Discovery (5) / STC Analysis 
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    Discovery (5) / STC Analysis

    Physical linchpin :
    1 , All expressional formula of physical law and theorem we have do not final ones for them ;
    2 , An certain physical process taking place in nature actually generates an cooresponding space time structure objectively and has space time value mathematically ;
    3 , Value of an characteristics physical quantity of this process equals product of this space time value and G gauge of physical dimension of this physical quantity.


    Recommendation :
    Given succession of this series discoveries , briefly reviewing discoveries prior to this one is strongly recommended .
    See those discoveries presented in Physics section of this forum at :
    Discovery of space time configuration for all physical units
    http://www.thescienceforum.com/Disco...its-12441t.php
    Discovery (2) / G Bubble Physical Process
    http://www.thescienceforum.com/Disco...ess-13102t.php
    Discovery (3) / Information Modulus of the Universe
    http://www.thescienceforum.com/Disco...rse-13193t.php
    Discovery (4) / General Physical Property Equation of the Universe
    http://www.thescienceforum.com/Disco...-Un-13299t.php


    STC analysis means an new method in physics which apply STC , STV and Default Theorem to mathematically analyze physical process .

    Definition : Default Space Time
    Supposed an physical quantity A =|A|dimA = |A| B m^a s^-b
    if STV(A) =STV(|A|Bm^a s^-b ) ≠ 1
    then called such physical quantity A as Default Space Time(DST).

    Default Theorem
    Supposed an physical process F = f [x(i),y(j),z(k) ] dimA , then
    F =STV{ f [y(j),z(k) ] } A(G) = STV{ f [y(j),z(k) ] } |A(G)| dimA
    here , x(i) represents CST ,y(j) default space time ,z(k) constant ,
    dimA dimensional expression of F , A(G) G gauge of dimA .

    Since value of most elementary physical constants are all equal and equal to 1 (belonging to completable space time as discussed before ) , so we can remove them from any physical equation without changing the result as obtained from traditional method .
    Example 1
    for gravitational law , by traditional method we have
    F =G [ M(1) M(2) / r^2 ]
    Let M(1) = M(2) = 1kg , and r = 1m , then we have :
    F = |G| N.
    By default theorem , we get :
    F = STV [ M(1) M(2) / r^2 ] N(G)
    F = STV [kg^2 / m^2 ] [ N / STV(|G|m^4 s^-4) ]
    = [1.8327730013788420...e+7 / 2.4686279637116245...e+34 ]^2
    [1 /0.8260600676546261...e-44 ] N
    =6.67259e-11 N = |G| N.
    Also from STC perspective , we can easily get :
    F = STC (kg^2 / m^2 ) = |G|^2 m^6 s^-4 / m^2 = |G| |G| m^4 s^-4 = |G| N.
    Same results compared to that of traditional ones .
    Example 2
    Claculating Energy-Frequency Formula by traditional method , we have :
    E = hv = |h| |v| J s s^-1 = |h| |v| J
    By default theorem , since h = 1 , so E = v , by Default theorem , we can get :
    E = STV(|v| s^-1) J(G)
    = STV(|v| s^-1) J / STV(|G| m^5 s^-4)
    = STV(|v| / |G|m^5 s^-3 ) J
    while STV ( 1 / |G|m^5 s^-3 ) = 6.6260755e-34 = |h| ,
    so E = |h| |v| J .
    Same result as traditional ones .
    Remark : Gh = [|G|m^5 s^-4 / J ] |h| Js = |G| |h| m^5 s^-3 = 1 .
    You can choose any physical law well established to exam Default Theorem , the result is always as same as those gotten from traditional method .
    Example 3
    Additionally , for an physical process under specific circumstances , as so many determined and unknown factors involved , it is impossible for us to establish an mathematical model to deal with , but there is a possibility for us to know space time value of the process through other channel . In such case , it make us possible to calculate out an correct result we seek without establishing such model . For instance , up to now , we can not find an mathematic model of the universe by which all physical properties of the universe can be figure out , such properties as total mass , radius , age , average mass density , total momentum of the universe and so on , fortunately we can obtain default space time value of the universe ( information modulus of the universe ) through an observed data of temperature of microwave background radiation of the universe . By this general default value of the universe , we can calculate out almost primary physical properties of the universe perfectly matching observations available so far .
    that is , by Default Theorem , we can get :
    Values of general physical properties of the universe
    = ( Information Modulus of the universe) × ( G gauges)
    .
    (Calculation results had been presented in discovery 3 and discovery 4 )

    Thousands year have spent to explore , generations have scarified to pursue by mankind , now all results verifiable are out there in such simple way , with extreme accuracy and unbelievable compatibility in between .

    Remark :
    By STC analysis , we can prove that total value of most of physical constants , such as Gravitational constant G , Speed of light constant c , Planck constant h , Avogadro constant N(A) , Boltzmann constant k(B) are all equal and equal to 1 , that is , STV(G) = STV(h) = STV(c) = STV(N(A)) = STV(k(B) ) = ... =1 .


    Refer to :
    STC Analysistechnique / Default Theorem
    http://www.universefedback.com/popularized_e/c4.htm

    To be continued
    Discovery (6) / Information Equation of the Universe

    Thanks for your reading.


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