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Thread: srdanova math

  1. #1 srdanova math 
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    questions
    1.Z(10^n)=?,Z-integers
    2.write in abbreviated form (if the function can be final and natural)
    2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
    2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
    2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
    3.how to solve this current knowledge of mathematics:
    along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c (image)
    yy.png
    Can mathematics explain the only two axiom that the rest are just evidence (experiments), if you think so join me show you Srdanova math, see you


     

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  3. #2  
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    How many times? Moved again


     

  4. #3  
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    Quote Originally Posted by Guitarist View Post
    How many times? Moved again
    Today I found where I was transferred Moderator forum-sorry-
    I figure this way, from education school has 12 years, I was always the subject of mathematics and physics had the best grades, math deal amateur, studying mathematics I came to know that mathematics can be simplified and be connected (to be explained only with two axiom) and extend the mathematics that can solve math problems that present no solution.
    a1.jpg
    Marjanovic Srdan
    M.Biljanica
    16201 Manojlovce
    Serbia
    ms.biljanica@gmail.com
    natural axiom
    What is " nature along "?
    -nature along in figure 1
    What is "point"?
    -start (end) natural long in figure 2
    a2.png
    What is the " basic rule "?
    -basic rule is determined that the two ( more) longer only have to connect the points
    [Sn]-mathematical facts
    [S1]-nature along
    [S2]-point (natural meaning of)
    Definition[natural along]-two points , distance between two points
    CM (current mathematics)-[S1]-does not know , [S2]-point is not defined , so anything and everything
    Last edited by msbiljanica; January 21st, 2012 at 07:57 AM.
     

  5. #4  
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    NATURAL MATHEMATICS



    Presupposition-natural long merge points in the direction of the first natural along AB
    Process:
    P1-AB..CD..ABC(AC)
    to read- natural along AB to point B, is connected to the natural long CD to point C, shall be
    P2-ABC(AC)..DE..ABCD(AD)
    read- along the ABC(AC) to point C , connecting with the natural long DE to point D is done
    renaming of points , we get along ABCD(AD)
    P3-ABCD(AD)..EF..ABCDE(AE)
    ...
    a3.jpg

    [S3]-along (natural basis)
    Definition[along]-the first and last point and the distance between points
    CM-[S3]-does not know
     

  6. #5  
    Brassica oleracea Strange's Avatar
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    It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
     

  7. #6  
    Moderator Moderator Markus Hanke's Avatar
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    I think what he is trying to say is that points and lines are really just two aspects of the same object; he then proceeds to show relationships between the two when you cut and re-assemble lines in various ways. It's basically topology.
    That's how I understand it anyway...I might be completely wrong though
     

  8. #7  
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    Quote Originally Posted by Strange View Post
    It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
    please calculated Z(10^n)=? ,and then we'll continue to talk
     

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    Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),...,
    (0,1,2,3,4,5,6,7,8,9 ),...
    Process:
    P1-N (0) = {0,00,000,0000,...}
    P2-N (0,1) = {0,1,10,11,100,...}
    ...
    P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
    ...
    a4.jpg
    [S4]-number along
    [S5]-set of natural numbers N
    We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...}
    Definition[number along]- a starting point (0), the last point at infinity
    [number N]-The number 0 is the point 0
    -Other numbers are longer, the first item is 0, the last
    point is the point of the name (number)
    CM-[S4].does not know , [S5]-axiom
     

  10. #9  
    Moderator Moderator Markus Hanke's Avatar
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    Quote Originally Posted by msbiljanica View Post
    Quote Originally Posted by Strange View Post
    It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
    please calculated Z(10^n)=? ,and then we'll continue to talk
    What are Z and n ?
    This is already a simple expression, what is there to calculate ?
     

  11. #10  
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    Quote Originally Posted by Markus Hanke View Post
    Quote Originally Posted by msbiljanica View Post
    Quote Originally Posted by Strange View Post
    It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
    please calculated Z(10^n)=? ,and then we'll continue to talk
    What are Z and n ?
    This is already a simple expression, what is there to calculate ?
    Z={...,-2,-1,0,1,2,...} , n={1,2,3,4,5,...}
     

  12. #11  
    Moderator Moderator Markus Hanke's Avatar
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    Quote Originally Posted by msbiljanica View Post
    Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),...,
    (0,1,2,3,4,5,6,7,8,9 ),...
    Process:
    P1-N (0) = {0,00,000,0000,...}
    P2-N (0,1) = {0,1,10,11,100,...}
    ...
    P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
    ...
    a4.jpg
    [S4]-number along
    [S5]-set of natural numbers N
    We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...}
    Definition[number along]- a starting point (0), the last point at infinity
    [number N]-The number 0 is the point 0
    -Other numbers are longer, the first item is 0, the last
    point is the point of the name (number)
    CM-[S4].does not know , [S5]-axiom
    So are you saying that you replace numbers with vectors in an abstract space ?
     

  13. #12  
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    Markus Hanke-o are you saying that you replace numbers with vectors in an abstract space
    numbers in the current mathematics are set axiom, I got the numbers from the previous evidence (along).
    along the same as the number (except for the number 0, which is the point), the vector is the number (along) in the plane (space)
     

  14. #13  
    Moderator Moderator Markus Hanke's Avatar
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    Quote Originally Posted by msbiljanica View Post
    Markus Hanke-o are you saying that you replace numbers with vectors in an abstract space
    numbers in the current mathematics are set axiom, I got the numbers from the previous evidence (along).
    along the same as the number (except for the number 0, which is the point), the vector is the number (along) in the plane (space)
    Yes, this is how I understand your notation. The thing is, how is that different from standard mathematics ? We already know that points in a plane ( or along a line ) can be described as vectors, or even just as complex numbers with a real and imaginary part.
    So what is different and new about your notation ( apart from it being, in my mind, rather cumbersome ) ?
     

  15. #14  
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    Presupposition-Numbers have their points
    Process:
    P1 0=(.0)
    P2 1={(.0),(.1)}
    P3 2={(.0),(.1),(.2)}
    P4 3={(.0),(.1),(.2),(.3)}
    P5 4={(.0),(.1),(.2),(.3),(.4)}
    ...
    a5.jpg
    [S6]-number points
    CM-[S6]does not know
     

  16. #15  
    Moderator Moderator Markus Hanke's Avatar
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    Quote Originally Posted by msbiljanica View Post
    Presupposition-Numbers have their points
    Process:
    P1 0=(.0)
    P2 1={(.0),(.1)}
    P3 2={(.0),(.1),(.2)}
    P4 3={(.0),(.1),(.2),(.3)}
    P5 4={(.0),(.1),(.2),(.3),(.4)}
    ...
    a5.jpg
    [S6]-number points
    CM-[S6]does not know
    Why is [S6] not known ? What does the [...] bracket denote ?
     

  17. #16  
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    Presupposition-numbers have opposite points
    Process:
    P1 0=(s.0)
    P2 1={(s.0),(s.1)}
    P3 2={(s.0),(s.1),(s.2)}
    P4 3={(s.0),(s.1),(s.2),(s.3)}
    P5 4={(s.0),(s.1),(s.2),(s.3),(s.4)}
    ...
    a6.jpg

    [S7]-number opposite points
    CM-[S7]does not know

    Markus Hanke-Why is [S6] not known ? What does the [...] bracket denote ?
    does not exist in the current math, so I brought his name tag and , [...] -designation of the term (math facts)
     

  18. #17  
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    Presupposition-numbers are comparable with each other
    Process:
    P1-two numbers (a, b) are comparable with each other - a> b, a =b, a <b, ).(=(>,=,<)
    P2-three numbers (a, b, c) are comparable with each other
    a7.jpg
    P3-four numbers (a, b, c, d) are comparable with each other
    a8.jpg
    ...
    [S8]-comparability
    numbers
    CM-[S8]known two of comparability, comparability of three numbers(a number comparable with the numbers b and c),
    comparability of the other knows.

     

  19. #18  
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    Presupposition-number ranges for number along
    Process:
    P1-image
    P2-image
    P3-image
    a9.png
    [S9]-mobility of number
    CM-[S9]-does not know
     

  20. #19  
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    Presupposition-Number (a) and mobile number (b ) of a contat ,merge
    Proces:
    P1 3+(.0/.0)2=3
    P2 3+(.1/.0)2=3
    P3 3+(.2/.0)2=4 - image
    P4 3+(.3/.0)2=5
    a10.jpg
    designation means the more we write (.0/.0) , unless specifically indicated to be
    P1 3+(.0)2=3
    P2 3+(.1)2=3
    P3 3+(.2)2=4
    P4 3+(.3)2=5
    General form
    a+(.0)b=c
    a+(.1)b=c
    ...
    a+(.d)b=c
    [S10]-addition
    CM-only form a+(s.0/.0)b=c , others do not know , axiom
    ______________________________________
    Presupposition-Number (a) and mobile number (b ) but have no contact with the item
    Process:
    P1 3(0)2
    P2 3(1)2
    P3 3(2)2
    ...
    a11.jpg
    Next - gap number and mobile number have no contact , except to point
    ...
    [S11]-gap number GN={a(b)c,...,g(f)...(d)e}
    [S12]-gap along
    Definition[gap along] a>0-0(0)0-point
    -0(a)0-two point ,separated by a gap
    -a(0)0,0(0)a,a(0)a-along , two points
    -a(a)a-two along , 4 points
    ...
    CM-[S11],[S12] -does no know
    ______________________________________________
    Third Now we can describe ( c ) the number of gaps ,10m(5m)5m
    PDF - srdanova math.pdf math.pdf
    Last edited by msbiljanica; January 25th, 2012 at 09:12 AM.
     

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    Presupposition-Gap number is comparable with the gap number and number
    Process:
    P1 a(b)c , a+(s.0)c=z
    P2 a(b)c(d)e , a+(s.0)c+(s.0)e=z
    P3 a(b)c(d)e(f)g ,a+(s.0)c+(s.0)e+(s.0)g=z
    ...
    number z as it compares as a number of
    [S13]-comparability gap numbers
    CM-[S13]-does no know
    __________________________________________________
    Presupposition-Adding the result can be written in short form:
    a) a+(s.0)0 , a+(s.0)b , a+(s.0)b+(s.0)b , ...,a+(s.0)b+...+(s.0)b
    b ) a+(s.0)b+...+(s.0)b,...,a+(s.0)b+(s.0)b, a+(s.0)b , a+(s.0)0
    Process:
    P1 - 3+(s.0)0=3 , 3+(s.0)4=7 , 347
    3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3411
    3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4+(s.0)4+(s.0)4=15 , 3415
    ...
    3+(s.0)0=3 , ... , 3+(s.0)4+...+(s.0)4=d , 34

    P2 - 3+(s.0)4+(s.0)4+(s.0)4=15 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4=7 , 3+(s.0)0=3 , 1543
    ...
    3+(s.0)4=7 , 3+(s.0)0=3 , 743
    General form -abc , ab
    [S14]-srcko
    CM-[S14]-does no know
     

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    Presupposition-Srcko can join a number not that can not be in the structure srcko
    Process:
    P1 101070 and 5 , 5_101070
    P2 5520 and 22 ,5520_22
    P3 75 and 25 , 75_25
    P4 68 and 2 ,2_68

    General form -abc_d , d_abc , ab_d ,d_ab
    [S15]-pendant srcko
    CM-[S15]-does no know
    Note-only one number can be pendand , number two goes into a complex srcko
    __________________________________________________ ________
    Presupposition-Two ( more ) srcko (pendand srcko) are combined into one unit
    Process:
    P1 106 and 118 , 106118
    P2 10565 and 703 ,10565_703
    P3 30360 and 45277_78 ,30360_45277_78
    ...
    General form -abcd, abc_de ,abc_def_g ,...
    [S16]-two ( more) srcko
    CM-[S16]-does no know
     

  23. #22  
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    Presupposition-Two ( more ) srcko have the first ( last) common number
    Process:
    P1 10530 and 3330 , 10533(_30)
    P2 4444 and 441094 and 44256 , 44(_44_)1094256
    ...
    General form -abcd(_e) , ab(_c_)defg , ...
    [S17]-two ( more) first-last srcko
    CM-[S17]-does no know
    __________________________________________________ ____
    Presupposition-In the expression a+(.b)c=d , d+(s.0)11 or d+(s.0)number (more) from 11
    Process:
    P1 3+(.s.0)5=8+(s.0)11 , 3+(s.0)5<91
    P2 5+(.0)5=5+(s.0)224 , 5+(.0)5<729
    ...
    General form - a+(.b)c=d+(s.0)11 ,a+(s.b)c<e1
    a+(.b)c=d+(s.0)e , a+(.b)c<f
    a+(.b)c=d+(s.0)efg , a+(.b)c<hij ...
    [S18]-left inequality
    CM-[S18]-know
    _______________________________________
    2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
    2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
    2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
    srcko
    5550={5,10,15,20,25,30,35,40,45,50}
    38350={38,41,44,47,50}
    501090={50,60,70,80,90}
    50792={50,57,64,71,78,85,92}
    two(more) first-last srcko
    55383(_50_)1090792
    remains part of the function, when we come to it
     

  24. #23  
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    If no one is responding to your posts, please STOP posting........
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    Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
    Process:
    P1 4-(.0)2=2
    P2 4-(.1)2=1(2)1 image
    P3 4-(.2)2=2
    P4 4-(.3)2=3(1)1
    P5 4-(.4)2=4(0)2
    a12.jpg
    General form
    a-(.0)b=c
    a-(.1)b=c
    ...
    a-(.d)b=c
    [S19]-subtraction
    CM-only form a-(s.0/s.0)b=c , others do not know , axiom
    __________________________________________________ _____________________
    Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
    Process:
    P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
    P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
    ...
    General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
    a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
    a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
    [S20]-right inequality addition
    CM-[S20]-know
     

  26. #25  
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    Paleo is quite right, if no one is interested enough to comment than don't continue to bump the thread. Locked.
    Start a blog or something.


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