1. questions
1.Z÷(10^n)=?,Z-integers
2.write in abbreviated form (if the function can be final and natural)
2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
3.how to solve this current knowledge of mathematics:
along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c (image)
yy.png
Can mathematics explain the only two axiom that the rest are just evidence (experiments), if you think so join me show you Srdanova math, see you

2.

3. How many times? Moved again

4. Originally Posted by Guitarist
How many times? Moved again
Today I found where I was transferred Moderator forum-sorry-
I figure this way, from education school has 12 years, I was always the subject of mathematics and physics had the best grades, math deal amateur, studying mathematics I came to know that mathematics can be simplified and be connected (to be explained only with two axiom) and extend the mathematics that can solve math problems that present no solution.
a1.jpg
Marjanovic Srdan
M.Biljanica
16201 Manojlovce
Serbia
ms.biljanica@gmail.com
natural axiom
What is " nature along "?
-nature along in figure 1
What is "point"?
-start (end) natural long in figure 2
a2.png
What is the " basic rule "?
-basic rule is determined that the two ( more) longer only have to connect the points
[Sn]-mathematical facts
[S1]-nature along
[S2]-point (natural meaning of)
Definition[natural along]-two points , distance between two points
CM (current mathematics)-[S1]-does not know , [S2]-point is not defined , so anything and everything

5. NATURAL MATHEMATICS

Presupposition-natural long merge points in the direction of the first natural along AB
Process:
P1-AB..CD..ABC(AC)
to read- natural along AB to point B, is connected to the natural long CD to point C, shall be
read- along the ABC(AC) to point C , connecting with the natural long DE to point D is done
renaming of points , we get along ABCD(AD)
...
a3.jpg

[S3]-along (natural basis)
Definition[along]-the first and last point and the distance between points
CM-[S3]-does not know

6. It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.

7. I think what he is trying to say is that points and lines are really just two aspects of the same object; he then proceeds to show relationships between the two when you cut and re-assemble lines in various ways. It's basically topology.
That's how I understand it anyway...I might be completely wrong though

8. Originally Posted by Strange
It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
please calculated Z÷(10^n)=? ,and then we'll continue to talk

9. Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),...,
(0,1,2,3,4,5,6,7,8,9 ),...
Process:
P1-N (0) = {0,00,000,0000,...}
P2-N (0,1) = {0,1,10,11,100,...}
...
P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
...
a4.jpg
[S4]-number along
[S5]-set of natural numbers N
We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...}
Definition[number along]- a starting point (0), the last point at infinity
[number N]-The number 0 is the point 0
-Other numbers are longer, the first item is 0, the last
point is the point of the name (number)
CM-[S4].does not know , [S5]-axiom

10. Originally Posted by msbiljanica
Originally Posted by Strange
It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
please calculated Z÷(10^n)=? ,and then we'll continue to talk
What are Z and n ?
This is already a simple expression, what is there to calculate ?

11. Originally Posted by Markus Hanke
Originally Posted by msbiljanica
Originally Posted by Strange
It is probably pointless repeatedly posting this stuff unless you make some effort to explain what it is all about. A random collection of diagrams and expressions don't convey anything.
please calculated Z÷(10^n)=? ,and then we'll continue to talk
What are Z and n ?
This is already a simple expression, what is there to calculate ?
Z={...,-2,-1,0,1,2,...} , n={1,2,3,4,5,...}

12. Originally Posted by msbiljanica
Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),...,
(0,1,2,3,4,5,6,7,8,9 ),...
Process:
P1-N (0) = {0,00,000,0000,...}
P2-N (0,1) = {0,1,10,11,100,...}
...
P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
...
a4.jpg
[S4]-number along
[S5]-set of natural numbers N
We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...}
Definition[number along]- a starting point (0), the last point at infinity
[number N]-The number 0 is the point 0
-Other numbers are longer, the first item is 0, the last
point is the point of the name (number)
CM-[S4].does not know , [S5]-axiom
So are you saying that you replace numbers with vectors in an abstract space ?

13. Markus Hanke-o are you saying that you replace numbers with vectors in an abstract space
numbers in the current mathematics are set axiom, I got the numbers from the previous evidence (along).
along the same as the number (except for the number 0, which is the point), the vector is the number (along) in the plane (space)

14. Originally Posted by msbiljanica
Markus Hanke-o are you saying that you replace numbers with vectors in an abstract space
numbers in the current mathematics are set axiom, I got the numbers from the previous evidence (along).
along the same as the number (except for the number 0, which is the point), the vector is the number (along) in the plane (space)
Yes, this is how I understand your notation. The thing is, how is that different from standard mathematics ? We already know that points in a plane ( or along a line ) can be described as vectors, or even just as complex numbers with a real and imaginary part.
So what is different and new about your notation ( apart from it being, in my mind, rather cumbersome ) ?

15. Presupposition-Numbers have their points
Process:
P1 0=(.0)
P2 1={(.0),(.1)}
P3 2={(.0),(.1),(.2)}
P4 3={(.0),(.1),(.2),(.3)}
P5 4={(.0),(.1),(.2),(.3),(.4)}
...
a5.jpg
[S6]-number points
CM-[S6]does not know

16. Originally Posted by msbiljanica
Presupposition-Numbers have their points
Process:
P1 0=(.0)
P2 1={(.0),(.1)}
P3 2={(.0),(.1),(.2)}
P4 3={(.0),(.1),(.2),(.3)}
P5 4={(.0),(.1),(.2),(.3),(.4)}
...
a5.jpg
[S6]-number points
CM-[S6]does not know
Why is [S6] not known ? What does the [...] bracket denote ?

17. Presupposition-numbers have opposite points
Process:
P1 0=(s.0)
P2 1={(s.0),(s.1)}
P3 2={(s.0),(s.1),(s.2)}
P4 3={(s.0),(s.1),(s.2),(s.3)}
P5 4={(s.0),(s.1),(s.2),(s.3),(s.4)}
...
a6.jpg

[S7]-number opposite points
CM-[S7]does not know

Markus Hanke-Why is [S6] not known ? What does the [...] bracket denote ?
does not exist in the current math, so I brought his name tag and , [...] -designation of the term (math facts)

18. Presupposition-numbers are comparable with each other
Process:
P1-two numbers (a, b) are comparable with each other - a> b, a =b, a <b, ).(=(>,=,<)
P2-three numbers (a, b, c) are comparable with each other
a7.jpg
P3-four numbers (a, b, c, d) are comparable with each other
a8.jpg
...
[S8]-comparability
numbers
CM-[S8]known two of comparability, comparability of three numbers(a number comparable with the numbers b and c),
comparability of the other knows.

19. Presupposition-number ranges for number along
Process:
P1-image
P2-image
P3-image
a9.png
[S9]-mobility of number
CM-[S9]-does not know

20. Presupposition-Number (a) and mobile number (b ) of a contat ,merge
Proces:
P1 3+(.0/.0)2=3
P2 3+(.1/.0)2=3
P3 3+(.2/.0)2=4 - image
P4 3+(.3/.0)2=5
a10.jpg
designation means the more we write (.0/.0) , unless specifically indicated to be
P1 3+(.0)2=3
P2 3+(.1)2=3
P3 3+(.2)2=4
P4 3+(.3)2=5
General form
a+(.0)b=c
a+(.1)b=c
...
a+(.d)b=c
CM-only form a+(s.0/.0)b=c , others do not know , axiom
______________________________________
Presupposition-Number (a) and mobile number (b ) but have no contact with the item
Process:
P1 ¤3(0)2¤
P2 ¤3(1)2¤
P3 ¤3(2)2¤
...
a11.jpg
Next - gap number and mobile number have no contact , except to point
...
[S11]-gap number GN={¤a(b)c¤,...,¤g(f)...(d)e¤}
[S12]-gap along
Definition[gap along] a>0-¤0(0)0¤-point
-¤0(a)0¤-two point ,separated by a gap
-¤a(0)0¤,¤0(0)a¤,¤a(0)a¤-along , two points
-¤a(a)a¤-two along , 4 points
...
CM-[S11],[S12] -does no know
______________________________________________
Third Now we can describe ( c ) the number of gaps ,¤10m(5m)5m¤
PDF - srdanova math.pdf math.pdf

21. Presupposition-Gap number is comparable with the gap number and number
Process:
P1 ¤a(b)c¤ , a+(s.0)c=z
P2 ¤a(b)c(d)e¤ , a+(s.0)c+(s.0)e=z
P3 ¤a(b)c(d)e(f)g¤ ,a+(s.0)c+(s.0)e+(s.0)g=z
...
number z as it compares as a number of
[S13]-comparability gap numbers
CM-[S13]-does no know
__________________________________________________
Presupposition-Adding the result can be written in short form:
a) a+(s.0)0 , a+(s.0)b , a+(s.0)b+(s.0)b , ...,a+(s.0)b+...+(s.0)b
b ) a+(s.0)b+...+(s.0)b,...,a+(s.0)b+(s.0)b, a+(s.0)b , a+(s.0)0
Process:
P1 - 3+(s.0)0=3 , 3+(s.0)4=7 , 347
3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3411
3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4+(s.0)4+(s.0)4=15 , 3415
...
3+(s.0)0=3 , ... , 3+(s.0)4+...+(s.0)4=d , 34

P2 - 3+(s.0)4+(s.0)4+(s.0)4=15 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4=7 , 3+(s.0)0=3 , 1543
...
3+(s.0)4=7 , 3+(s.0)0=3 , 743
General form -abc , ab
[S14]-srcko
CM-[S14]-does no know

22. Presupposition-Srcko can join a number not that can not be in the structure srcko
Process:
P1 101070 and 5 , 5_101070
P2 5520 and 22 ,5520_22
P3 75 and 25 , 75_25
P4 68 and 2 ,2_68

General form -abc_d , d_abc , ab_d ,d_ab
[S15]-pendant srcko
CM-[S15]-does no know
Note-only one number can be pendand , number two goes into a complex srcko
__________________________________________________ ________
Presupposition-Two ( more ) srcko (pendand srcko) are combined into one unit
Process:
P1 106 and 118 , 106118
P2 10565 and 703 ,10565_703
P3 30360 and 45277_78 ,30360_45277_78
...
General form -abcd, abc_de ,abc_def_g ,...
[S16]-two ( more) srcko
CM-[S16]-does no know

23. Presupposition-Two ( more ) srcko have the first ( last) common number
Process:
P1 10530 and 3330 , 10533(_30)
P2 4444 and 441094 and 44256 , 44(_44_)1094256
...
General form -abcd(_e) , ab(_c_)defg , ...
[S17]-two ( more) first-last srcko
CM-[S17]-does no know
__________________________________________________ ____
Presupposition-In the expression a+(.b)c=d , d+(s.0)11 or d+(s.0)number (more) from 11
Process:
P1 3+(.s.0)5=8+(s.0)11 , 3+(s.0)5<91
P2 5+(.0)5=5+(s.0)224 , 5+(.0)5<729
...
General form - a+(.b)c=d+(s.0)11 ,a+(s.b)c<e1
a+(.b)c=d+(s.0)e , a+(.b)c<f
a+(.b)c=d+(s.0)efg , a+(.b)c<hij ...
[S18]-left inequality
CM-[S18]-know
_______________________________________
2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
srcko
5550={5,10,15,20,25,30,35,40,45,50}
38350={38,41,44,47,50}
501090={50,60,70,80,90}
50792={50,57,64,71,78,85,92}
two(more) first-last srcko
55383(_50_)1090792
remains part of the function, when we come to it

24. If no one is responding to your posts, please STOP posting........

25. Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
Process:
P1 4-(.0)2=2
P2 4-(.1)2=¤1(2)1¤ image
P3 4-(.2)2=2
P4 4-(.3)2=¤3(1)1¤
P5 4-(.4)2=¤4(0)2¤
a12.jpg
General form
a-(.0)b=c
a-(.1)b=c
...
a-(.d)b=c
[S19]-subtraction
CM-only form a-(s.0/s.0)b=c , others do not know , axiom
__________________________________________________ _____________________
Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
Process:
P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
...
General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
CM-[S20]-know

26. Paleo is quite right, if no one is interested enough to comment than don't continue to bump the thread. Locked.
Start a blog or something.

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