1. If any of you more advanced math-types know fractional calculus, would you care to work out D<sup>1.5</sup>x<sup>2</sup> and post the answer you get? I just recently came across the concept of fractional calculus and started working with it, and decided to try out D<sup>1.5</sup>x<sup>2</sup>. I arrived at an answer but would like to know if I'm correct. Thanks.

2.

3. Well, by definition D<sup>1.5</sup>x<sup>2</sup> = Γ(2+1) ∕ Γ(2−1.5+1) · (x<sup>2−1.5</sup>) = Γ(3) ∕ Γ(1.5) · (√x). So you just need to work out the gamma-function values. Γ(3) is easy; it’s just 2! = 2; I think Γ(1.5) is ½√π.

So the answer is … 4√(x ⁄ π)?

4. Looks good to me.

5. That's what I got, good. I know it's pretty simple, I just wanted to make sure I didn't mess it up somehow.

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