http://www.thescienceforum.com/Calcu...ions-8994t.php

Ok, starting on the chapter 3 review.

Calculate y'

7) y= e<sup>sin 2Θ</sup>

From what I currently know, I would conclude that:

y' = e<sup>sin 2Θ</sup>

since if

a = e<sup>b</sup>

then

a' = e<sup>b</sup>

However, since the book gives the answer as

(2 cos 2Θ)e<sup>sin 2Θ</sup>

then I suspect that there must be a method involved to take the derivative of the exponent of e to get that answer, however I have not yet found it.