Notices
Results 1 to 3 of 3

Thread: function continuity proof

  1. #1 function continuity proof 
    Forum Freshman
    Join Date
    Jun 2005
    Posts
    14
    function continuity proof

    --------------------------------------------------------------------------------

    hello:
    here is my problem:
    if a function f(x)is continuous in [0,1],and its scope is also [0,1],then there must be one point e to make f(e)=e
    if i use the theorem a continuous function can have any return value between upper and lower bound,then i can have
    e belong to [0,1],and there will be a vulue a to make f(a)(a also belong to the same definition scope[0,1])to have a value e,but how can i promise the there can must be a chance in which a=e

    any comment is appreciated.


    Reply With Quote  
     

  2.  
     

  3. #2  
    Moderator Moderator
    Join Date
    Jun 2005
    Posts
    1,629
    Are you sure you copied this correctly? The usual form would be;
    if f is continuous in [0,1], then there is an a in [0,1] such that f(0)<f(a)<f(1), and you may set f(a) = e.

    If you insist also that f(e) = e, then either f is trivial, or e = 0, And if f(a) = e = f(e), then a = e, but I can't beleive you stated the problem correctly


    Reply With Quote  
     

  4. #3  
    Forum Sophomore
    Join Date
    Jul 2005
    Posts
    121
    The probelm is fine as stated.

    Hint: consider the function g(x)=f(x)-x. Apply intermediate value theorem.
    Reply With Quote  
     

Bookmarks
Bookmarks
Posting Permissions
  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •