Thread: Find two 4 digit numbers that multiply to give 4^8 + 6^8 + 9^8

The whole puzzle is in the title. It took a friend of mine, in his own words, "3 pages of factoring (correcting and replacing)". It took me 6 lines. Take a challenge?

Step 1:
4⁸ + 6⁸ + 9⁸ = 2^2*8 + 2⁸*3⁸ + 3^2*8

(2^(3*8)-3^(3*8))/(2^8-3^8)

\frac{2^{3*8}-3^{3*8}}{(2^8-3^8)}