Thread: Fun for the brain II

It looks like my previous thread received no complement, instead people raged at me a great deal.

So yeah this is another one, I hope people favour it this time.


1.
2. Tom and Jake are climbing up stairs. Tom is at the first floor, heading to the forth; Jake is on the fifth, heading to the eighth. Their speed are the same. When Tom reaches the forth, is Jake on the eighth floor?

3. In a race you exceed the second one, what's your position?
4. i⁴ⁿ+i⁴ⁿ⁺¹+i⁴ⁿ⁺²+i⁴ⁿ⁺³⁼


The first to answer all CORRECTLY wins.

and i have no idea what question 3 is asking.

Originally Posted by Wise Man

It looks like my previous thread received no complement, instead people raged at me a great deal.

So yeah this is another one, I hope people favour it this time.


1.
2. Tom and Jake are climbing up stairs. Tom is at the first floor, heading to the forth; Jake is on the fifth, heading to the eighth. Their speed are the same. When Tom reaches the forth, is Jake on the eighth floor?

3. In a race you exceed the second one, what's your position?
4. i⁴ⁿ+i⁴ⁿ⁺¹+i⁴ⁿ⁺²+i⁴ⁿ⁺³⁼


The first to answer all CORRECTLY wins.

question 3.) second

Originally Posted by Wise Man

It looks like my previous thread received no complement, instead people raged at me a great deal.

Wise Man, we were only joking

So yeah this is another one, I hope people favour it this time.

I will, just as I did the previous Here are my answers:

1) . This is really a trick question since you think you can multiply the terms under the radical, but I think that doesn't apply to when both are negative. So, I say i*sqrt(2) times i*sqrt(5) = -sqrt(10). Tada.

2) There's a lot of major details you didn't specify, but I'll assume the very norm of the problem. Yes. They will reach their destinations at the same time (assuming stairway lengths are equal, they began at the same time, etc.)

3) Looks like a trick question or riddle of some kind. I'm gonna say ... first?

4) Assuming n is some integer, zero. Because no matter what value for n you have, you will have a sum of i and -i and 1 and -1, summing to 0.

hmm... Chrisgorlitz answered #3 correctly, and wallaby answered #1,#2 & #4 correctly, halorealm answered #1,#2,#4 correctly, #3 incorrectly.

It seems none of you answered ALL CORRECTLY.

#3 is kinda tricky, if you are in a race, if you exceed the second, your original position must have been the THIRD, thus you become the second one afterwards.

Originally Posted by Wise Man

#3 is kinda tricky, if you are in a race, if you exceed the second, your original position must have been the THIRD, thus you become the second one afterwards.

That was a good one, haha. I do understand that. I just didn't know what I was reading. At first I thought it was talking about the race in #2, then I thought it was some question about time ("second 1") in a race or something. I didn't get it so I just threw something out :P

Originally Posted by Wise Man

#3 is kinda tricky, if you are in a race, if you exceed the second, your original position must have been the THIRD, thus you become the second one afterwards.

Not if you also "exceed" (whatever that means) the first as well.

maybe the word surpass would be more suitable.

Originally Posted by Wise Man

maybe the word surpass would be more suitable.

Or "beat"? (It still doesn't work, though.)

Okay. How about "pass". You pass the car in 2nd. You are now in 2nd place.

Not if you also passed the guy in first

It's ambiguous. It could mean you passed the person who was in second (and is now third) or it could mean you passed the one who is now in second (and was in first).