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Thread: Prove that P = a ± b?

  1. #1 Prove that P = a ± b? 
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    ABSTRACT.
    The aim of this proof is to create a system that can solve itself without human intervention which encompasses an AI choice mechanism, a self awareness system and a model for an expanding universe.
    The AI choice mechanism and the self awareness system is after the model must have been created.


    Basic number theory shows that it is possible to combine any number by the addition of two other suitable numbers.Still in general, it is not impossible to prove that P = a ± b because the said "Proof P = a ± b" support the infinite list of possible numbers which when added together sum to any given number.

    The proof:
    Prove that P = a ± b? using a formula. (Optional: when P ≠ a ± b at a point to infinity i.e. when P = 1 to both positive infinity and negative infinity).Given that P is arbitrary number where a and b are entities of the arbitrary number.

    The knowledge base (encapsulated, appropriate for public use):
    Prove that A = B when A ≠ B at a point to infinity i.e. a point to both positive infinity and negative infinity.

    Note: Both the Proof and the knowledge base amount to the same thing.


    Firstly, in order establish that P ≠ a ± b.
    Let's consider that a = P where P is arbitrary number.
    a + b = P implies a - P = -b.
    a - b = P implies a - P = +b.
    Thereby ±b can equally occupy a given space.
    And If and only if -b = b when b = 0.
    Then the logic demands that a + b = a - b.
    Such that P = a(+b - b).
    Therefore for every negative b, there is a positive b where P is arbitrary number.
    So that P = a(0)
    Also that P = 0
    Thus P ≠ P and P ≠ a ± b end.

    Note:If we can generate a proof that P = a ± b.Then P = a ± b can resurrect from here.


    Since 0 = 1 in quantum mechanics and 0 = 1 is infinite with the Proof P = a ± b.
    Therefore P = a(1) and P = a.
    Since a = P when P = 1.
    Then P = 1.
    Thus P = P and P = a ± b end.

    However, P = P with the proof P = a ± b where 0 = 1 at a certain point of the application.
    Alternatively, P = P if 0 = 1 like in quantum mechanics but it has a limit.
    Though the proof P = a ± b has no limit.So the proof P = a ± b can aid "0 = 1" in quantum mechanics!



    Now.
    From the proof P = a ± b which implies a - P = ±b.
    Let's consider that: a - P = ±b.
    To the extent that: a - P = 0( + b - b ).
    Such that a - P = 0(0).

    REASON {THE ENTANGLEMENT}:
    Importantly, both the proof P = a ± b and the knowledge base simultaneously yielded equal variables until b = 0.
    When b = 0, the proof P = a ± b yielded -b and the knowledge base yielded b respectively.
    Therefore +b and -b can coexist but logic demands that -b = b when b = 0.
    Thus everything amount to zero (0).

    Also.
    From the Knowledge base:
    Given that B is the existence of A.
    If A ≠ B.Then there is no evidence to show that A and B exist to an extent that B is not visible at this point.
    Therefore, A and B are consider to be nonexistent illusion when A ≠ B.
    If A = B.Then there is an evidence to show that A once existed and B exist to an extent that B is visible at this point.
    Thus B is the only evidence that A once existed.

    ILLUSTRATION:
    Assuming space system is the domain that hold each group of orientation in space according to the concept.
    While movement (m) is movement of an object (P) in space from an infinite origin.

    Now, let's assume this orientation in space, ( -b, 0 , b ) or ( b, 0, -b ) is in relation with the expansion of the universe.Such that we have the following result at each movement (m) ranging from a negative infinity to a positive infinity passing through the origin 0.i.e
    From an infinite origin...


    The Proof P = a ± b at a certain system yields this where system here is considered to be the difference between P and b from a + b = P:

    At this stage before the turning point P ≠ a ± b or A ≠ B.
    When movement (m) = -5 contraction of the universe is ( -3.0, 0, 3.0 )
    When movement (m) = -4 contraction of the universe is ( -2.5, 0, 2.5 )
    When movement (m) = -3 contraction of the universe is ( -2.0, 0, 2.0 )
    When movement (m) = -2 contraction of the universe is ( -1.5, 0, 1.5 )
    When movement (m) = -1 contraction of the universe is ( -1.0, 0, 1.0 )
    When movement (m) = 0 contraction of the universe is ( -0.5, 0, 0.5 )

    When movement (m) = 1 size of the universe is ( 0, 0, 0 )
    Thereby there is a turning here and a turning point can be determined.
    Note: P is consider to loose its form when movement(m) ≤ 1 i.e when P ≤ 1.Thereby b is not visible until when P ≥ 2.

    At this stage after the turning point P = a ± b or A = B when A ≠ B.

    When movement (m) = 2 expansion of the universe is ( 0.5, 0, -0.5 )
    When movement (m) = 3 expansion of the universe is ( 1.0, 0, -1.0 )
    When movement (m) = 4 expansion of the universe is ( 1.5, 0, -1.5 )
    When movement (m) = 5 expansion of the universe is ( 2.0, 0, -2.0 )
    When movement (m) = 6 expansion of the universe is ( 2.5, 0, -2.5 )
    When movement (m) = 7 expansion of the universe is ( 3.0, 0, -3.0 )
    This continue to infinity...

    Thus:
    Let consider that when contraction of the universe is in DISORDER or CHAOS ( -b, 0, b ) is less than or equal to ( -0.5, 0, 0.5 ).
    Such that there is a turning point when expansion of the universe is ( 0, 0, 0 ).
    So that there is a turning when expansion of the universe is in ORDER ( b, 0, -b ) is greater than or equal to ( 0.5, 0, -0.5 ).

    Therefore the turning point which is the point of the big bang could be determine when there is a sufficient reason.

    This tells us that DISORDER beget ORDER.i.e DISORDER = ORDER.

    Therefore, the universe can be said to be homogeneous in this manner for every arbitrary number as it is expanding from when b = 0 to infinity, when b ≠ 0.

    As a result, lightest element i.e. hydrogen atom “lifted” in a linear super positioning would be an appropriate tool for the model.


    All this explanation is in relation with what quantum entanglement is all about.


    What we're doing is also to generate something out of nothing where nothing is quantified as space.



    Wisdom is needed to understand all that i have written.
    Wisdom is the right application of knowledge.
    It's a math for singularity.
    Cheers!


     

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  3. #2 Re: Prove that P = a ± b? 
    . DrRocket's Avatar
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    Quote Originally Posted by opoint
    ABSTRACT.
    The aim of this proof is to create a system that can solve itself without human intervention which encompasses an AI choice mechanism, a self awareness system and a model for an expanding universe.
    The AI choice mechanism and the self awareness system is after the model must have been created.


    Basic number theory shows that it is possible to combine any number by the addition of two other suitable numbers.Still in general, it is not impossible to prove that P = a ± b because the said "Proof P = a ± b" support the infinite list of possible numbers which when added together sum to any given number.

    The proof:
    Prove that P = a ± b? using a formula. (Optional: when P ≠ a ± b at a point to infinity i.e. when P = 1 to both positive infinity and negative infinity).Given that P is arbitrary number where a and b are entities of the arbitrary number.

    The knowledge base (encapsulated, appropriate for public use):
    Prove that A = B when A ≠ B at a point to infinity i.e. a point to both positive infinity and negative infinity.

    Note: Both the Proof and the knowledge base amount to the same thing.


    Firstly, in order establish that P ≠ a ± b.
    Let's consider that a = P where P is arbitrary number.
    a + b = P implies a - P = -b.
    a - b = P implies a - P = +b.
    Thereby ±b can equally occupy a given space.
    And If and only if -b = b when b = 0.
    Then the logic demands that a + b = a - b.
    Such that P = a(+b - b).
    Therefore for every negative b, there is a positive b where P is arbitrary number.
    So that P = a(0)
    Also that P = 0
    Thus P ≠ P and P ≠ a ± b end.

    Note:If we can generate a proof that P = a ± b.Then P = a ± b can resurrect from here.


    Since 0 = 1 in quantum mechanics and 0 = 1 is infinite with the Proof P = a ± b.
    Therefore P = a(1) and P = a.
    Since a = P when P = 1.
    Then P = 1.
    Thus P = P and P = a ± b end.

    However, P = P with the proof P = a ± b where 0 = 1 at a certain point of the application.
    Alternatively, P = P if 0 = 1 like in quantum mechanics but it has a limit.
    Though the proof P = a ± b has no limit.So the proof P = a ± b can aid "0 = 1" in quantum mechanics!



    Now.
    From the proof P = a ± b which implies a - P = ±b.
    Let's consider that: a - P = ±b.
    To the extent that: a - P = 0( + b - b ).
    Such that a - P = 0(0).

    REASON {THE ENTANGLEMENT}:
    Importantly, both the proof P = a ± b and the knowledge base simultaneously yielded equal variables until b = 0.
    When b = 0, the proof P = a ± b yielded -b and the knowledge base yielded b respectively.
    Therefore +b and -b can coexist but logic demands that -b = b when b = 0.
    Thus everything amount to zero (0).

    Also.
    From the Knowledge base:
    Given that B is the existence of A.
    If A ≠ B.Then there is no evidence to show that A and B exist to an extent that B is not visible at this point.
    Therefore, A and B are consider to be nonexistent illusion when A ≠ B.
    If A = B.Then there is an evidence to show that A once existed and B exist to an extent that B is visible at this point.
    Thus B is the only evidence that A once existed.

    ILLUSTRATION:
    Assuming space system is the domain that hold each group of orientation in space according to the concept.
    While movement (m) is movement of an object (P) in space from an infinite origin.

    Now, let's assume this orientation in space, ( -b, 0 , b ) or ( b, 0, -b ) is in relation with the expansion of the universe.Such that we have the following result at each movement (m) ranging from a negative infinity to a positive infinity passing through the origin 0.i.e
    From an infinite origin...


    The Proof P = a ± b at a certain system yields this where system here is considered to be the difference between P and b from a + b = P:

    At this stage before the turning point P ≠ a ± b or A ≠ B.
    When movement (m) = -5 contraction of the universe is ( -3.0, 0, 3.0 )
    When movement (m) = -4 contraction of the universe is ( -2.5, 0, 2.5 )
    When movement (m) = -3 contraction of the universe is ( -2.0, 0, 2.0 )
    When movement (m) = -2 contraction of the universe is ( -1.5, 0, 1.5 )
    When movement (m) = -1 contraction of the universe is ( -1.0, 0, 1.0 )
    When movement (m) = 0 contraction of the universe is ( -0.5, 0, 0.5 )

    When movement (m) = 1 size of the universe is ( 0, 0, 0 )
    Thereby there is a turning here and a turning point can be determined.
    Note: P is consider to loose its form when movement(m) ≤ 1 i.e when P ≤ 1.Thereby b is not visible until when P ≥ 2.

    At this stage after the turning point P = a ± b or A = B when A ≠ B.

    When movement (m) = 2 expansion of the universe is ( 0.5, 0, -0.5 )
    When movement (m) = 3 expansion of the universe is ( 1.0, 0, -1.0 )
    When movement (m) = 4 expansion of the universe is ( 1.5, 0, -1.5 )
    When movement (m) = 5 expansion of the universe is ( 2.0, 0, -2.0 )
    When movement (m) = 6 expansion of the universe is ( 2.5, 0, -2.5 )
    When movement (m) = 7 expansion of the universe is ( 3.0, 0, -3.0 )
    This continue to infinity...

    Thus:
    Let consider that when contraction of the universe is in DISORDER or CHAOS ( -b, 0, b ) is less than or equal to ( -0.5, 0, 0.5 ).
    Such that there is a turning point when expansion of the universe is ( 0, 0, 0 ).
    So that there is a turning when expansion of the universe is in ORDER ( b, 0, -b ) is greater than or equal to ( 0.5, 0, -0.5 ).

    Therefore the turning point which is the point of the big bang could be determine when there is a sufficient reason.

    This tells us that DISORDER beget ORDER.i.e DISORDER = ORDER.

    Therefore, the universe can be said to be homogeneous in this manner for every arbitrary number as it is expanding from when b = 0 to infinity, when b ≠ 0.

    As a result, lightest element i.e. hydrogen atom “lifted” in a linear super positioning would be an appropriate tool for the model.


    All this explanation is in relation with what quantum entanglement is all about.


    What we're doing is also to generate something out of nothing where nothing is quantified as space.



    Wisdom is needed to understand all that i have written.
    Wisdom is the right application of knowledge.
    It's a math for singularity.
    Cheers!
    You realize, do you not, that is total rubbish. What is not trivial is wrong.

    BTW P=P+0. There are infinitely many other choices for a and b. All you need is that a=P-b.


     

  4. #3  
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    Mod note I have already moved one version of this nonsense to Pseudo. Please do not post here again, otherwise I will see to it that you get banned.

    Get me?
     

  5. #4  
    Guest
    Quote Originally Posted by Guitarist
    Mod note I have already moved one version of this nonsense to Pseudo. Please do not post here again, otherwise I will see to it that you get banned.

    Get me?
    What did he do that was so wrong? Competence is not a choice.
     

  6. #5  
    Forum Isotope
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    but participation on a math forum is a choice. And in the face of the knowledge that you are not competent, it would be a wise choice not to post on a math forum.
    Wise men speak because they have something to say; Fools, because they have to say something.
    -Plato

     

  7. #6  
    Guest
    Quote Originally Posted by Arcane_Mathematician
    but participation on a math forum is a choice. And in the face of the knowledge that you are not competent, it would be a wise choice not to post on a math forum.
    What did he/she do that was so wrong to deserve such a warning?
     

  8. #7  
    . DrRocket's Avatar
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    Quote Originally Posted by Ellatha
    Quote Originally Posted by Arcane_Mathematician
    but participation on a math forum is a choice. And in the face of the knowledge that you are not competent, it would be a wise choice not to post on a math forum.
    What did he/she do that was so wrong to deserve such a warning?
    As you should be able to recognize, that entire voluminous post is meaningless gibberish. The issue is not one of competence in mathematics,though perhaps one of mental competence in the larger sense.

    You know this well enough and appear to be simply trolling yourself. There is no merit in the OP and nothing to be gained from further discussion.
     

  9. #8  
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    Quote Originally Posted by Ellatha
    What did he/she do that was so wrong to deserve such a warning?
    Ellatha. If you, or anyone else for that matter, disagrees with a moderator's action in this or any other sub-forum, please PM to them in the first instance, or to SkinWalker or InSanity in the second.

    It is considered poor form to dispute moderators' actions in public, so much so it could result in action being taken against you.

    Thread locked
     

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