How would one solve this;
where y is a function of x??
would appreciate any help.

How would one solve this;
where y is a function of x??
would appreciate any help.
i see 1 equation with 2 unknowns.
what do we have to solve?
oops my bad, its alright i know how to solve it now. You are supposed to get
Originally Posted by Heinsbergrelatz
Product rule or chain rule, one or the other, look em up I forget them.
Maybe both who knows?
so x= y sin y^2
so for xsiny^2 dx/dy = 2ycos y^2
So dx/dy = sin y^2 + y2y cos y^2
= sin y^2 + 2y^2 cos y^2
thus dy/dy=
................ 1
= 
sin y^2 + 2y^2 cos y^2
Is that the answer?
no.Originally Posted by smokey
The answer is simply
That is dx/dy I believe not dy/dxOriginally Posted by Arcane_Mathematician
Bit of a trick really.
we have to express only in terms of y and x, sorry for not noting all the details. so its supposed to be;
That looks a bit ropey to me.
well that is the only possible case when expressing the derivative in terms of x and y, got any other alternatives if you say its "ropey"?
He's absolutely correct.Originally Posted by smokey
Originally Posted by Arcane_Mathematician
Who me?
Yes he is correct, I did not notice what he did initially but looking again
I see he substituted back in the initial equation into the result to get a
simpler answer,
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