This is not homework; I'm just curious. And would like to know if there is another way to calculate this:
(12/32)*(11/31)*(10/30)...*(2/20)*(1/19)
Without having to enter all of the fractions in a calculator?
Thank you.

This is not homework; I'm just curious. And would like to know if there is another way to calculate this:
(12/32)*(11/31)*(10/30)...*(2/20)*(1/19)
Without having to enter all of the fractions in a calculator?
Thank you.
Find common factors in nominators and denominators and reduce.
The first thing that meets the eye is 12/32 = (3*4)/(8*4) = 3/8.
But you can reduce between the individual fractions, as they are all being multiplied by each other  so the 11 in the second fraction can be reduced with the 22 in the last fraction but three.
Of course this will be more work than typing everything into a calculator, but it may be worth it, for example if you want to avoid the digital errors of floatingpoint numbers and get a proper fraction as a result.
Good luck, and keep us posted  L.
Hey, there is something wrong! Exactly how many fractions do you have in your expression?
From 12 to 1 inclusive, with a step of 1, you have 12 numerators.
But from 32 to 19 inclusive, with a step of 1, you have 14 denominators.
Am I missing something?
Oh.. Yeah, I think it's supposed to be: (12/32)*(11/31)*(10/30)...*(2/22)*(1/11)Originally Posted by Leszek Luchowski
Sorry
That is worse. Now you have 12 terms based on the numerators and 23 terms based on the denominators.Originally Posted by IAlexN
Do you really mean (12/32)*(11/31)*(10/30)...*(2/22)*(1/21) ?
In which case the product is 12!*20!/32!
Yes, that is correct, I meant 1/21. I once again apologize; I was in a hurry and never noticed my mistake, thank you for acknowledging that.Originally Posted by DrRocket
Might someone elaborate as to how you reached 12!*20!/32!, as I'm not entirely sure how you reached the 20! in your answer.
20!/32! = 1/(32*31*30*...*21)Originally Posted by IAlexN
Thank you.Originally Posted by DrRocket
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