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hi all,..
i posted from few days topic says my professor challenge,..and i tried to solve this out but i didnt get it,..but my friend gut it
the question was saying:
find all pythagriam Triples (with no common division between a,b&c).(i wasnt so clear in presenting the q in the last topic so here it is again )
well my friend shoot that:
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a number (n) : squared minus 1,4 can NEVER give a number (n) : squared..
example 9- 1= 8, 9- 4= 5
so there is No common factor that: (c) is Odd: Csq
To divide an odd no. squared : is odd into 2 nos.: squared, one square must be even and the other sjould be odd..
Now let Asq be odd and B sq be even so: A is odd and B is even.
somehow b is always equal to C- 1
so the problem is in A:
so we can made the form like:
A B C
3 1(3+1) 1(3+1) +1
5 2(5+1) 2(3+1) +1
7 3(7+1) 3(7+1) +1
9 4(9+1) 4(9+1) +1
SO, the triplets are:
( n; nsq-1/2 ; nsq +1/2)
when n is odd n is (3,5,7,....)
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All Rights Reserved to my Friend ™
,..actully i was not close to my friend's solution, i like this answer,..seems like numbers game,..
