1. A-level integration is really bothering me, and i would appreciate if anyone could help me with this question.

given that x=1, and t=0, solve the differential equation; hence: express this function given a subject to   2. ### Related Discussions:

3. It's the easiest dif. eq. there is. All you have to do is separate the variables and you get dt=100/(x^2-(10-x)dx. Integration gives you t=(x*log(x)-x*log(x-10)-10)/x+C. Since t=0 when x=1, you have 0=1*0-1*log(-9)-10/1=-9.954242509 + 1.36437635 i, therefore C approx 9.95-1.36i.

Of course, I have been known to be wrong before, and it is odd that your problem involves complex numbers. Eh, I've prolly made a mistake somewhere, but I can't figure out where.  4. I worked this out without any imaginary numbers, but I used that fancy little trick that matt A used to get there. The problem with that is that it's cheating or something.  5. Originally Posted by Heinsbergrelatz
A-level integration is really bothering me, and i would appreciate if anyone could help me with this question.

given that x=1, and t=0, solve the differential equation; hence: express this function given a subject to HAve you made a mistake here?

Shgouldnt it be not ie dt/dx not dx/dt?  Bookmarks
 Posting Permissions
 You may not post new threads You may not post replies You may not post attachments You may not edit your posts   BB code is On Smilies are On [IMG] code is On [VIDEO] code is On HTML code is Off Trackbacks are Off Pingbacks are Off Refbacks are On Terms of Use Agreement