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Thread: Very simple but still...

  1. #1 Very simple but still... 
    Forum Freshman IAlexN's Avatar
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    Hi, I'm really struggling with this question.

    2^(square root of x) = 8

    I know that x, just by quickly looking at the equation is, is 9. However, I've no idea how I can solve this equation; showing that x = 9.

    Could someone please help me.


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  3. #2 Re: Very simple but still... 
    . DrRocket's Avatar
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    Quote Originally Posted by IAlexN
    Hi, I'm really struggling with this question.

    2^(square root of x) = 8

    I know that x, just by quickly looking at the equation is, is 9. However, I've no idea how I can solve this equation; showing that x = 9.

    Could someone please help me.






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  4. #3  
    Forum Freshman IAlexN's Avatar
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    Thank you for you reply DrRocket. However is there any other way to solve the equation, without using logarithm. Because, I haven't started to study logarithm yet.
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  5. #4  
    Forum Ph.D. Heinsbergrelatz's Avatar
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    this is the approach my maths teacher tells the ordinary or the standard mathematics level students in our year level.





    same base thereby;



    square to both sides to eliminate the ;






    i cannot think of any other way than this.
    ------------------




    "Mathematicians stand on each other's shoulders."- Carl Friedrich Gauss


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  6. #5  
    . DrRocket's Avatar
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    Quote Originally Posted by Heinsbergrelatz
    this is the approach my maths teacher tells the ordinary or the standard mathematics level students in our year level.





    same base therby;



    square to both sides to eliminate the ;







    i cannot think of any other way than this.
    That works. You have implicitly used the logarithm base 2, but that is perfectly OK.
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  7. #6  
    Forum Freshman IAlexN's Avatar
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    Thanks for your answer Heinsbergrelatz, it was very helpful :-D

    Quote Originally Posted by DrRocket
    That works. You have implicitly used the logarithm base 2, but that is perfectly OK.
    However, just out of curiosity what does logarithm base 2 actually mean?
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  8. #7  
    Forum Ph.D. Heinsbergrelatz's Avatar
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    Thanks for your answer Heinsbergrelatz, it was very helpful
    Your welcome :-D
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  9. #8  
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    Quote Originally Posted by IAlexN
    Thanks for your answer Heinsbergrelatz, it was very helpful :-D

    Quote Originally Posted by DrRocket
    That works. You have implicitly used the logarithm base 2, but that is perfectly OK.
    However, just out of curiosity what does logarithm base 2 actually mean?
    is a way to rewrite . Logarithm base 2 just sets up a function to determine what is at some y. It isolates x in the equation in a solvable way.
    Wise men speak because they have something to say; Fools, because they have to say something.
    -Plato

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  10. #9  
    . DrRocket's Avatar
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    Quote Originally Posted by Arcane_Mathematician
    Quote Originally Posted by IAlexN
    Thanks for your answer Heinsbergrelatz, it was very helpful :-D

    Quote Originally Posted by DrRocket
    That works. You have implicitly used the logarithm base 2, but that is perfectly OK.
    However, just out of curiosity what does logarithm base 2 actually mean?
    is a way to rewrite . Logarithm base 2 just sets up a function to determine what is at some y. It isolates x in the equation in a solvable way.
    precisely
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  11. #10  
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    Quote Originally Posted by IAlexN
    Thanks for your answer Heinsbergrelatz, it was very helpful :-D

    Quote Originally Posted by DrRocket
    That works. You have implicitly used the logarithm base 2, but that is perfectly OK.
    However, just out of curiosity what does logarithm base 2 actually mean?
    Have you studied growth and decay yet?
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