Hi, I'm really struggling with this question.
2^(square root of x) = 8
I know that x, just by quickly looking at the equation is, is 9. However, I've no idea how I can solve this equation; showing that x = 9.
Could someone please help me.

Hi, I'm really struggling with this question.
2^(square root of x) = 8
I know that x, just by quickly looking at the equation is, is 9. However, I've no idea how I can solve this equation; showing that x = 9.
Could someone please help me.
Thank you for you reply DrRocket. However is there any other way to solve the equation, without using logarithm. Because, I haven't started to study logarithm yet.
this is the approach my maths teacher tells the ordinary or the standard mathematics level students in our year level.
same base thereby;
square to both sides to eliminate the ;
i cannot think of any other way than this.
That works. You have implicitly used the logarithm base 2, but that is perfectly OK.Originally Posted by Heinsbergrelatz
Thanks for your answer Heinsbergrelatz, it was very helpful :D
However, just out of curiosity what does logarithm base 2 actually mean?Originally Posted by DrRocket
Your welcome :DThanks for your answer Heinsbergrelatz, it was very helpful
is a way to rewrite . Logarithm base 2 just sets up a function to determine what is at some y. It isolates x in the equation in a solvable way.Originally Posted by IAlexN
preciselyOriginally Posted by Arcane_Mathematician
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