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  1. #1 0 quantity 
    Forum Ph.D. Heinsbergrelatz's Avatar
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    is there any mathematical solution to or there can be any constant infront of "e" e.g.

    thank you


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  3. #2  
    Forum Radioactive Isotope MagiMaster's Avatar
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    There are no real solutions to either, but there are infinitely many imaginary ones.


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  4. #3  
    Forum Ph.D. Heinsbergrelatz's Avatar
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    so what would be the answer to the "infinite" imaginary solutions??

    do we have to use a graph?? so in equations such as ??
    what is the route we take?
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  5. #4  
    Forum Radioactive Isotope MagiMaster's Avatar
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    Not an infinite imaginary solution, but infinitely many solutions in the complex plane
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  6. #5  
    Forum Ph.D. Heinsbergrelatz's Avatar
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    so its rather like no solution, simply because we cant posses a finite number of solutions in questions like this.
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  7. #6  
    Forum Ph.D. Leszek Luchowski's Avatar
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    I don't see why you would call for imaginary numbers. There is no finite solution for . The absolute value of approaches zero as the real part of x approaches negative infinity. Whether or not x has an imaginary part is irrelevant, it will just rotate around zero in the complex plane, without bringing it any closer or further away.
    Leszek. Pronounced [LEH-sheck]. The wondering Slav.
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  8. #7  
    . DrRocket's Avatar
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    Quote Originally Posted by MagiMaster
    There are no real solutions to either, but there are infinitely many imaginary ones.
    There are no imaginary one either since
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  9. #8  
    Forum Ph.D. Heinsbergrelatz's Avatar
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    ah i see now, thank you~
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  10. #9  
    Forum Radioactive Isotope MagiMaster's Avatar
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    Crud. It's been too long since I last messed with complex numbers. I just remembered the formula wrong. For some reason, I was ignoring the imaginary part of the result.
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