alright, this bit of homework has really got to me, so I will post the original question here, along with the work I've done. Please help me out guys:
Calculate the surface integralWhere
and S is the entire sphere
with outward orientation
SO, the tip I got from lectures is that we are basically only considering F on S. So:
I redifined S in terms of spherical coordinates such thatbecause the radius is a constant, I don't need to consider it (as independent) when I make the parameterized surface, since it is always 3. I can rewrite the integrals now as:
and, because I switched to spherical coordinates, I also need a jacobian of
which, in this case, is
Now, I take the derivative of this separetly with respect to each variable, and then cross them (still the tips from the lectures), which would, effectively, be
=
=
okay, that all said, here is where it's my own brain, and I feel like I've missed something obvious, but here goes anyway.
for my varibles,
the fun part:
=
and I have no idea where to go from here. I only combined like terms and pulled out a
... any helpful hints appreciated.


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Where
and S is the entire sphere
with outward orientation
because the radius is a constant, I don't need to consider it (as independent) when I make the parameterized surface, since it is always 3. I can rewrite the integrals now as:
and, because I switched to spherical coordinates, I also need a jacobian of
which, in this case, is 
=
=




= 

and I have no idea where to go from here. I only combined like terms and pulled out a
... any helpful hints appreciated.

becomes
which, when we substitute back in our original problems we get:
which becomes:
and, as the last 2 terms are opposites, they cancel, and all I have is
which, when evaluated over spherical coordinates, becomes
if I'm not mistaken. Which, will evaluate to:
which is, more elegantly,
, yes?
-- and just substitute the radius of 3 and multiply by the constant that you are integrating which is 3 again. You can do the whole problem without evaluating a single integral directly.



