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Thread: ODE y'(x) = (2x + y(x))^2

  1. #1 ODE y'(x) = (2x + y(x))^2 
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    Hi, friends!

    I've tried to solve that ODE but the solution found ( y(x) = -2x + 2^0.5 tg[ 2^0.5 (x + k)] ) isn't good:

    its derivative doesn't correspond to (2x +y(x))^2.

    I don't know why..


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  3. #2  
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    ps: k is the arbitrary constant.


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  4. #3  
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    One of my calculation mistakes as everytime I use a paper too messed up!

    The solution found is right.

    Forgive me!
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