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Thread: Chance of being dealt a pair if another player has a pair.

  1. #1 Chance of being dealt a pair if another player has a pair. 
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    Basically each player is dealt a two cards from a standard pack.
    One player drops his cards and you see that he has a pair (a pair of jacks for example).

    Now, you have not looked at your cards yet, but given this information, is it
    a) more likely your cards are a pair. (any pair)
    b) less likelly your cards are a pair.(any pair)
    c) makes no difference.(any pair)


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  3. #2  
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    More likely:

    Probs are:

    no information about other hand - PA=3/51
    information that other hand has pair - PB=P1+P2
    P1= prob if your first card is same as pair =2/(50x49)
    P2 = prob if your first card is different = (48x3)/(50x49)

    calculation

    PA = .058823
    PB = .059592


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  4. #3  
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    Quote Originally Posted by mathman
    More likely:

    Probs are:

    no information about other hand - PA=3/51
    information that other hand has pair - PB=P1+P2
    P1= prob if your first card is same as pair =2/(50x49)
    P2 = prob if your first card is different = (48x3)/(50x49)

    calculation

    PA = .058823
    PB = .059592

    If your first card is the same as the other players, pair. Your odds are higher then getting four of a kind in one hand. The fact that all four cards have to be in order, might take the odds way out there. Unless you get a lazy or lucky shuffle of a new deck.

    Sincerely,


    William McCormick
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  5. #4  
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    Ain't google great!
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  6. #5  
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    if your first card is the same as the other players, the odds of you getting a 4 of a kind is the same as his, and it depends on the community draws. this deals with Hold'um, not stud.
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