Would anyone know the formula to find the center of gravity of an isosceles triangle. Looking down upon the geometric isosceles triangle from a top view, I would like to anchor something to its balance point.

I am sure there is a formula for that. I just do not know what it is.

I do not know if it is more then just splitting up the square inches. Because of the lever action involved.

A perfect triangle would be easy. Just find the center.

Sincerely,

William McCormick