1. all even numbers are formed from 2. and assuming that half of the numbers in a set of natural numbers are even can we conclude that 2 is the most abundant prime number?

2.

3. Originally Posted by parag1973
all even numbers are formed from 2. and assuming that half of the numbers in a set of natural numbers are even can we conclude that 2 is the most abundant prime number?
I think you mean “most abundant prime factor”.

Well, this is not my area, unfortunately. I’ll leave the other experts to answer your question.

4. 1/2 of all numbers are divisible by 2. 1/3 of all numbers are divisible by 3. 1/5 of all numbers are divisible by 5. etc. So what?

5. Originally Posted by parag1973
all even numbers are formed from 2. and assuming that half of the numbers in a set of natural numbers are even can we conclude that 2 is the most abundant prime number?

Actually all even and odd numbers are formed from one. Ha-ha.

Sincerely,

William McCormick

6. Originally Posted by parag1973
all even numbers are formed from 2. and assuming that half of the numbers in a set of natural numbers are even can we conclude that 2 is the most abundant prime number?
You must either formulate your question in a more sophisticated way, and I don't quite know what that would be, or accept that there are a countably infinite number of even numbers, a countably infinite number of odd numbers divisible by three, .....

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