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Thread: Electron Configuration & Atomic Structure Please Help!

  1. #1 Electron Configuration & Atomic Structure Please Help! 
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    The electron configuration of atoms is a pretty important sequence of numbers:


    1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 (Hydrogen to Palladium)

    Essentially the electron sequence:

    2, 2, 6, 2, 6, 2, 10, 6, 1, 10

    If you isolate the 1/2 electron spin:

    1s1 2s1 2p3 3s1 3p3 4s1 3d5 4p3 5s1 4d5

    or the sequence:

    1 1 3 1 3 1 5 3 1 5

    The prime number sequence is an equally important sequence of numbers:

    3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53...

    If you isolate the number gaps between the primes

    i.e.

    2 & 3 = 0
    3 & 5 = 1 (number 4)
    5 & 7 = 1 (number 5)
    7 & 11 = 3 (numbers 8,9,10) etc

    Number gaps in the prime sequence:

    1 1 3 1 3 1 3 5 1 5

    Electrons configuration 1/2 spin:

    1 1 3 1 3 1 5 3 1 5

    There is a correlation between these sequences other than the 3d5 & 4p3:

    1 1 3 1 3 1 3 5 1 5 (Primes Gaps)

    1s1 2s1 2p3 3s1 3p3 4s1 3d5 4p3 5s1 4d5

    and that is where it gets even more interesting...

    1 1 3 1 3 1 3 5 1 5 (Primes Gaps)


    1s1 2s1 2p3 3s1 3p3 4s1 4p3 3d5 5s1 4d5 (Electron Configuration from Hydrogen to Cadmium)


    Okay so the 4p and 3d are in the wrong order... why?


    What is the difference between p and d?


    P orbital or electrons in an 0 orbit


    had to delete images... due to forum restrictions


    d orbital or electrons in an 8 orbit... (#orbit = probability shells the primes are the key infrascturture)


    had to delete images... due to forum restrictions


    There is a significant difference...


    p orbitals contain 2 electrons on each axis x, y and z


    d orbitals contain ONLY 1 electron on each axis AND occupy the same space as the px, py, pz, s = 4 electrons


    had to delete images... due to forum restrictions


    and in between the x, y and z 6 electrons


    had to delete images... due to forum restrictions


    So essentially the electrons in the d occupy 10 axis NOT 5... and are in the "same space" as the p and s BUT they go through the middle of the nucleus as there is only 1 electron per axis...


    So the d orbitals occupy:


    4s1, 4p3, 3d5, 5s1 BUT across the axis so they also occupy the - 4s1, - 4p3, -3d5, -5s1 with the SAME electron... = 10 electrons


    I haven't looked at the f orbitals I thought I would let this sink in first - so please don't bombard me with f lol

    Okay so what do you think?


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  3. #2  
    Bullshit Intolerant PhDemon's Avatar
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    Pure nonsense numerology...


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  4. #3  
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    Quote Originally Posted by PhDemon View Post
    Pure nonsense numerology...
    and you are?
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  5. #4  
    Bullshit Intolerant PhDemon's Avatar
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    Irrelevant question, but to answer I'm a chemist with a PhD in this stuff...
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  6. #5  
    exchemist
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    Quote Originally Posted by DanKing View Post
    The electron configuration of atoms is a pretty important sequence of numbers:


    1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 (Hydrogen to Palladium)

    Essentially the electron sequence:

    2, 2, 6, 2, 6, 2, 10, 6, 1, 10

    If you isolate the 1/2 electron spin:

    1s1 2s1 2p3 3s1 3p3 4s1 3d5 4p3 5s1 4d5

    or the sequence:

    1 1 3 1 3 1 5 3 1 5

    The prime number sequence is an equally important sequence of numbers:

    3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53...

    If you isolate the number gaps between the primes

    i.e.

    2 & 3 = 0
    3 & 5 = 1 (number 4)
    5 & 7 = 1 (number 5)
    7 & 11 = 3 (numbers 8,9,10) etc

    Number gaps in the prime sequence:

    1 1 3 1 3 1 3 5 1 5

    Electrons configuration 1/2 spin:

    1 1 3 1 3 1 5 3 1 5

    There is a correlation between these sequences other than the 3d5 & 4p3:

    1 1 3 1 3 1 3 5 1 5 (Primes Gaps)

    1s1 2s1 2p3 3s1 3p3 4s1 3d5 4p3 5s1 4d5

    and that is where it gets even more interesting...

    1 1 3 1 3 1 3 5 1 5 (Primes Gaps)


    1s1 2s1 2p3 3s1 3p3 4s1 4p3 3d5 5s1 4d5 (Electron Configuration from Hydrogen to Cadmium)


    Okay so the 4p and 3d are in the wrong order... why?


    What is the difference between p and d?


    P orbital or electrons in an 0 orbit


    had to delete images... due to forum restrictions


    d orbital or electrons in an 8 orbit... (#orbit = probability shells the primes are the key infrascturture)


    had to delete images... due to forum restrictions


    There is a significant difference...


    p orbitals contain 2 electrons on each axis x, y and z


    d orbitals contain ONLY 1 electron on each axis AND occupy the same space as the px, py, pz, s = 4 electrons


    had to delete images... due to forum restrictions


    and in between the x, y and z 6 electrons


    had to delete images... due to forum restrictions


    So essentially the electrons in the d occupy 10 axis NOT 5... and are in the "same space" as the p and s BUT they go through the middle of the nucleus as there is only 1 electron per axis...


    So the d orbitals occupy:


    4s1, 4p3, 3d5, 5s1 BUT across the axis so they also occupy the - 4s1, - 4p3, -3d5, -5s1 with the SAME electron... = 10 electrons


    I haven't looked at the f orbitals I thought I would let this sink in first - so please don't bombard me with f lol

    Okay so what do you think?
    What I think is that this is totally misguided.

    Why don't you just read up why the numbers come out the way they do? They are just spherical harmonics. The sequence is s, s+p, s+p+d, s + p +d + f, and so on, with numbers 2 for s, 6 for p, 10 for d 14 for f, and so on. There can be 2 electrons to each orbital, by Pauli's exclusion principle. And that's it.

    The order in which these orbitals are filled follows the Aufbau principle. 4s starts to be filled before 3d due to the way the shielding of nuclear charge turns out as the nuclear charge and the number of electrons increases (4s is pulled down in energy a bit faster than 3d as nuclear charge goes up, due to the greater penetration of the electron cloud by s orbitals). But a decent 6th form chemistry student could tell you how that works. No need for unphysical numerology based on primes. Chemists understand perfectly well why the sequence is the way it is.

    The pattern arises from the solutions to Schroedinger's Wave Equation for an atom. The only stable electron states are standing waves. Just as a violin string has natural standing wave frequencies fundamental and overtones, so do the electrons circulating round an atom. I can point you in the direction of further reading if you are interested.
    Last edited by exchemist; September 1st, 2017 at 06:12 PM.
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