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parag1973
Posted: Sat May 10, 2008 6:59 am    Post subject: division Reply with quote

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what is division?
1 7
2 6
3 5
4 4
what is the concept of division?
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thyristor
Posted: Sat May 10, 2008 11:51 am    Post subject: Reply with quote

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Division can be seen as repeatedly subtraction of the denominator from the numerator. The result of the operation is how many times you can subtract the denominator from the numerator.
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river_rat
Posted: Sun May 11, 2008 9:37 am    Post subject: Reply with quote

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thyristor, that doesn't help explain (pi+1)/e easily. In general, a/b is defined to be the element x (if it exists) from what ever collection you are working in (groups, rings, graded algebra's etc) such that a = x * b

So 21/7 = 3 since 21 = 3*7 Smile
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thyristor
Posted: Sun May 11, 2008 1:01 pm    Post subject: Reply with quote

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Sorry, I din't get what he meant by the sequence of numbers.
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river_rat
Posted: Sun May 11, 2008 10:29 pm    Post subject: Reply with quote

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No idea either...
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JaneBennet
Posted: Mon May 12, 2008 4:32 am    Post subject: Reply with quote

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river_rat wrote:
thyristor, that doesn't help explain (pi+1)/e easily. In general, a/b is defined to be the element x (if it exists) from what ever collection you are working in (groups, rings, graded algebras etc) such that a = x * b

So 21/7 = 3 since 21 = 3*7 Smile

If it exists, it has to be unique as well – otherwise it’s not defined. 0/0 (in a field) is not defined because it’s not unique: 0 = 0·0 = 1·0.
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river_rat
Posted: Mon May 12, 2008 10:43 pm    Post subject: Reply with quote

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right and left divisors need not be unique though JaneBennet - you need a cancellation property usually for that to work if i recall.
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JaneBennet
Posted: Tue May 13, 2008 5:02 am    Post subject: Reply with quote

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And the cancellation property fails for 0 in a field because 0 does not have a multiplicative inverse in a field.

What I’m trying to say is

Quote:
a/b is defined to be the element x (if it exists) from what ever collection you are working in (groups, rings, graded algebras etc) such that a = x * b

if b = 0, you cannot define a/b uniquely this way for the purpose of division. It would mean division by 0.
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river_rat
Posted: Tue May 13, 2008 10:41 pm    Post subject: Reply with quote

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I was heading more towards semigroups without cancellation where the zero problem explodes Smile
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