Thread: need help on algorithm

hi all...this is my first time here.
i have this problem.which is related to generator,item,binary setting and input. i have a lot of conditions where generators from 2 to 6 with different binary setting.
generator 2: needs 3 or more items
generator 3: needs 4 or more items
generator 4: needs 5 or more items
generator 5:needs 6 or more items
generator 6: needs 7 or more item.

user just need to key in the input and select generator....

items is depend on input.the example is like this:


Input [0] [1] [2] [3]
[0] a0 b0 c0 d0
[1] a1 b1 c1 d1
[2] a2 b2 c2
[3] a3
item 1 2 3 4
Generator=2
Bi set
0 0 1 1
O/p X X c0 d0
X X c0 d1
X X c1 d0
X X c1 d1
X X c2 d0
X X c2 d1

Binary setting
0 1 0 1
O/p X b0 X d0
X b0 X d1
X b1 X d0
X b1 X d1
X b2 X d0
X b2 X d1

Binary setting
0 1 1 0
O/p X b0 c0 X
X b0 c1 X
X b0 c2 X
X b1 c0 X
X b1 c1 X
X b1 c2 X
X b2 c0 X
X b2 c1 X
X b2 c2 X

Binary setting
1 0 1 0
O/p a0 X c0 X
a0 X c1 X
a0 X c2 X
a1 X c0 X
a1 X c1 X
a1 X c2 X
a2 X c0 X
a2 X c1 X
a2 X c2 X
a3 X c0 X
a3 X c1 X
a3 X c2 X

Binary setting
1 1 0 0
O/p a0 b0 X X
a0 b1 X X
a0 b2 X X
a1 b0 X X
a1 b1 X X
a1 b2 X X
a2 b0 X X
a2 b1 X X
a2 b2 X X
a3 b0 X X
a3 b1 X X
a3 b2 X X

Binary setting
1 0 0 1
O/p a0 X X d0
a0 X X d1
a1 X X d0
a1 X X d1
a2 X X d0
a2 X X d1
a3 X X d0
a3 X X d1

Generator=3
Binary setting
0 1 1 1
O/p X b0 c0 d0
X b0 c0 d1
X b0 c1 d0
X b0 c1 d1
X b0 c2 d0
X b0 c2 d1
X b1 c0 d0
X b1 c0 d1
X b1 c1 d0
X b 1 c1 d1
X b 1 c2 d0
X b 1 c2 d1
X b 2 c0 d0
X b 2 c0 d1
X b 2 c1 d0
X b 2 c1 d1
X b 2 c2 d0
X b 2 c2 d1


Binary setting
1 1 1 0
O/p a0 b 0 c0 X
a0 b0 c1 X
a0 b0 c2 X
a0 b1 c0 X
a0 b1 c1 X
a0 b1 c2 X
a0 b2 c0 X
a0 b2 c1 X
a0 b2 c2 X
a1 b0 c0 X
a1 b0 c1 X
a1 b0 c2 X
a1 b1 c0 X
a1 b1 c1 X
a1 b1 c2 X
a1 b2 c0 X
a1 b2 c1 X
a1 b2 c2 X
a2 b0 c0 X
a2 b0 c1 X
a2 b0 c2 X
a2 b1 c0 X
a2 b1 c1 X
a2 b1 c2 X
a2 b2 c0 X
a2 b2 c1 X
a2 b2 c2 X
a3 b0 c0 X
a3 b0 c1 X
a3 b0 c2 X
a3 b1 c0 X
a3 b1 c1 X
a3 b1 c2 X
a3 b2 c0 X
a3 b2 c1 X
a3 b2 c2 X

Binary setting
1 0 1 1
O/p a0 X c0 d0
a0 X c0 d1
a0 X c1 d0
a0 X c1 d1
a0 X c2 d0
a0 X c2 d1
a1 X c0 d0
a1 X c0 d1
a1 X c1 d0
a1 X c1 d1
a1 X c2 d0
a1 X c2 d1
a2 X c0 d0
a2 X c0 d1
a2 X c1 d0
a2 X c1 d1
a2 X c2 d0
a2 X c2 d1
a3 X c0 d0
a3 X c0 d1
a3 X c1 d0
a3 X c1 d1
a3 X c2 d0
a3 X c2 d1

Binary setting
1 1 0 1
O/p a0 b0 X d0
a0 b0 X d1
a0 b1 X d0
a0 b1 X d1
a0 b2 X d0
a0 b2 X d1
a1 b0 X d0
a1 b0 X d1
a1 b1 X d0
a1 b1 X d1
a1 b2 X d0
a1 b2 X d1
a2 b0 X d0
a2 b0 X d1
a2 b1 X d0
a2 b1 X d1
a2 b2 X d0
a2 b2 X d1
a3 b0 X d0
a3 b0 X d1
a3 b1 X d0
a3 b1 X d1
a3 b2 X d0
a3 b2 X d1



Example for generator more than 3.
*must have more than 3 input a,b,c and d and can be more.

Input (example)
Items 1 2 3 4 5
a0 b0 c0 d0 e0
a1 b1 c1 d1 e1
b2 d2

Gen Binary setting
3 0 0 1 1 1
0 1 0 1 1
0 1 1 0 1
0 1 1 1 0
1 0 0 1 1
1 0 1 0 1
1 0 1 1 0
1 1 0 0 1
1 1 1 0 0

4
0 1 1 1 1
1 0 1 1 1
1 1 0 1 1
1 1 1 0 1
1 1 1 1 0
[/code]
to get binary setting actually depends on how many items and what is generator selected.the number of '1' in binary setting is equal to the number of generator.
5 and 6 are not allowed to generate the output with this input because item is only 5.

the problem is i dont know how to relate input and binary setting.i have no problem to get binary setting,generator and input.