1. I have a solution of HCl and i want to neautralize it with Ca(OH)2
I have 440,25 kg of HCl
How much Ca(OH)2 will i need, if the HCl solution is:

a) 32% per volume
b) 32% per weight

How much sediment at the bottom?

2.

3. Oh my. Those take-home tests can be so pesky.

Well, you can at least get started by posting for us the neutralization equation, balanced. Then we'll do the next step.
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4. YOU HAVE 440 KG of HCL!!!!!!!

5. Ca(OH)2 + 2HCl > CaCl2 + H20

CaCl2 is the sediment.

Yes i have 440 kg HCl. 30% per weight is that from the solution the 0,3*440 are HCl?

6. no one help me?

7. Thats not quite balanced... You need 2H^2O

P.S. How do you do sub or super script here...

8. ok now that is balanced which are the answers to my questions (pleeaasseee )

9. OK, so we know that 1 mole of calcium hydroxide is neutralized by 2 moles of HCl. Give us the weights (masses) of a mole of calcium chloride and a mole of HCl. Then we can tackle the math.

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