Hi all,
Finding this question very hard.
Here is a cell:
I2(aq), I-(aq) | Pt +0.54V
Fe2+(aq) | Fe(s) -0.44V
Here is my cell diagram and emf value:
Fe2+(aq) | Fe(s) ⁞ I2(aq), I-(aq) | Pt
emf = E(cell) = E(RHS) – E(LHS)
emf = E(cell) = (+0.54) –(-0.44)
emf = E(cell) = +0.98V
I am now tasked with writing balanced ionic equations that occur when the cell is discharged.
Any help would be very much appreciated. Thanks.