1. So we have the Rydberg's Formula for 1 electron system such as Hydrogen or Helium Ion or any other one electron system.

DeltaE = -2.18 x 1018(1/nfinal2 - 1/ninitial2)

Though I came across, I new formula for the first time just now.

DeltaE = (-Z2/n2)R ---> R = -2.18 x 1018 J or 3.39 x 1015 Hz

So I'm guessing that the second equation can be used for both 1 electron and multi-electron systems? What is this formula called btw?

2.

3. Originally Posted by AndresKiani
So we have the Rydberg's Formula for 1 electron system such as Hydrogen or Helium Ion or any other one electron system.

DeltaE = -2.18 x 1018(1/nfinal2 - 1/ninitial2)

Though I came across, I new formula for the first time just now.

DeltaE = (-Z2/n2)R ---> R = -2.18 x 1018 J or 3.39 x 1015 Hz

So I'm guessing that the second equation can be used for both 1 electron and multi-electron systems? What is this formula called btw?
I'm rusty on the details of all this, but I rather think your second formula is Rydberg's formula for hydrogen-like atoms (i.e. ions with only one electron left). Have a look here: Rydberg formula - Wikipedia, the free encyclopedia

Once you have more than one electron present, you get electron-electron repulsions and so the relationship of energy to nuclear charge becomes impossible to calculate exactly.

4. Originally Posted by exchemist
Originally Posted by AndresKiani
So we have the Rydberg's Formula for 1 electron system such as Hydrogen or Helium Ion or any other one electron system.

DeltaE = -2.18 x 1018(1/nfinal2 - 1/ninitial2)

Though I came across, I new formula for the first time just now.

DeltaE = (-Z2/n2)R ---> R = -2.18 x 1018 J or 3.39 x 1015 Hz

So I'm guessing that the second equation can be used for both 1 electron and multi-electron systems? What is this formula called btw?
I'm rusty on the details of all this, but I rather think your second formula is Rydberg's formula for hydrogen-like atoms (i.e. ions with only one electron left). Have a look here: Rydberg formula - Wikipedia, the free encyclopedia

Once you have more than one electron present, you get electron-electron repulsions and so the relationship of energy to nuclear charge becomes impossible to calculate exactly.
Yeah.. I just saw this formula and I was thinking that Z would be replaced by any atomic number. But as you said, for multi e- systems we would have to calculate the full electromagnetic field and its interactions which is a pain.

5. Originally Posted by AndresKiani
Originally Posted by exchemist
Originally Posted by AndresKiani
So we have the Rydberg's Formula for 1 electron system such as Hydrogen or Helium Ion or any other one electron system.

DeltaE = -2.18 x 1018(1/nfinal2 - 1/ninitial2)

Though I came across, I new formula for the first time just now.

DeltaE = (-Z2/n2)R ---> R = -2.18 x 1018 J or 3.39 x 1015 Hz

So I'm guessing that the second equation can be used for both 1 electron and multi-electron systems? What is this formula called btw?
I'm rusty on the details of all this, but I rather think your second formula is Rydberg's formula for hydrogen-like atoms (i.e. ions with only one electron left). Have a look here: Rydberg formula - Wikipedia, the free encyclopedia

Once you have more than one electron present, you get electron-electron repulsions and so the relationship of energy to nuclear charge becomes impossible to calculate exactly.
Yeah.. I just saw this formula and I was thinking that Z would be replaced by any atomic number. But as you said, for multi e- systems we would have to calculate the full electromagnetic field and its interactions which is a pain.
Yes, especially since, to make matters even worse, s, p, d, f etc orbitals have different shapes and degrees of penetration of one another's envelopes. Hence the individuality of the chemical elements, of course…....

6. Originally Posted by AndresKiani
But as you said, for multi e- systems we would have to calculate the full electromagnetic field and its interactions which is a pain.
Awards prize for the understatement of the millennium

7. Originally Posted by PhDemon
Originally Posted by AndresKiani
But as you said, for multi e- systems we would have to calculate the full electromagnetic field and its interactions which is a pain.
Awards prize for the understatement of the millennium
I certainly wouldn't know how the Hartree-Fock to go about it.

8. Your Gaussian is as good as mine...

9. Originally Posted by PhDemon
Your Gaussian is as good as mine...
Touché! Very good.

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