Hi there! I'm going over some past papers for a university and found this question...unfortunately they don't give the ANSWERS

The problem is: Apatite (Ca5(PO4)3F) is used to manufacture fertilizer. How many kilograms of pure phosphorus (P) is included in 1150 kg of apatite?

I found the molar masses to be as follows:

Ca: 40.08

P: 30.974

O: 15.999

F: 18.998

What I did was added them up as shown in the formula (i.e. 40.08 x 5 + (30.974 + 15.999 x 4) x 3 + 18.998 = 504.308) then I divided the amount of phosphorous (3 x 30.974) by the total amount (504.308) and got approx. 0.184 ...I'm not sure if that step was right but I kept going! Since the amount of phosphorous makes up 0.184 of the total amount I went 1150(kg) x 0.184 and got approx. 211.9 kilograms.

SO basically my answer is 211.9 kg but I have no idea if it is right or completely wrong! Can someone please help me?

Thank you all!