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Thread: Orbital hybridisation

  1. #1 Orbital hybridisation 
    NOF
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    according to this molecule:


    i need to write the orbital hybridisation for any carbon atoms.
    so all except 1 will be SP2 ?

    thanks.


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  3. #2  
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    Indeed all are sp except the one in the bottom (the methyl), that one is sp configured.

    a simple trick to 'cheat' that I like to use goes like this:
    - count the number of binding partners the C-atom has.
    eg. any carbon in the benzene ring has a double cargon (1), a single carbon (2) and a hydrogen (3) as binding partners.
    - substract 1 from your number of BP's
    eg. 3 binding partners - 1 = 2 --> sp

    # BP = 4 --> sp
    # BP = 3 --> sp
    # BP = 2 --> sp


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  4. #3 wow 
    NOF
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    this is great way what you gave me.

    thank you very much.

    now the last thing i asked about this molecule if it have a Dipole, i know that Dipole Caused by Electronegativity between 2 different atoms, for example F-O so the Dipole will be to the F side because this atom has more Electronegativity.
    but in this molecule i go lost, because every dipole pulls to another direction.


    so i am not sure if this molecule as a Dipole.


    thanks again.
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  5. #4  
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    I'm not aware of a way to simply glance at a molecule and find it's dipole.

    on the other hand I can say it will probably have one.
    If you look at but substituted parts of the benzene ring, we have the following

    -COOH
    -OCOCH3

    The top one, the carboxyl, has a pretty negative oxygen (at the double bond) with 2 free pairs on top.
    The carbon is connected to another cargon (same EN) and 2 oxygens, both pulling. It'l be a delta positive carbon next to a delta negative oxygen.

    In the second group the carbon is allso adjacent to 2 oxygens pulling, but the C it's connected to is part of a methylgroup, which makes it a slightly negative C (pulling from 3x H).
    It will stabilize the carbon in the second group due to the mesomeric effect.

    So my guess would be that there is definately a dipole. To state exactly where it is... it's a combination of factors really.
    I think you'd need to start calculating with vectors and the likes to find out where it is.
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  6. #5 hi, 
    NOF
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    thanks for answer.

    i not need to know exactly where there is the dipole,
    only to say in general if this molecule as a dipole.

    thanks.
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