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Thread: Experiment

  1. #1 Experiment 
    Forum Bachelors Degree The P-manator's Avatar
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    I did this experiment. I am not sure about my equation, however, if I am correct, there is a little something that caught my eye.

    NaCl + H2SO4 --> NaSO4 + H2Cl*

    *What is this?


    Pierre

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  3. #2  
    Forum Sophomore NimaRahnemoon's Avatar
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    I personally think this equation makes more sense:

    2NaCl + H2SO4 --> Na2SO4 + 2HCl

    Here everything is clear:

    NaCl: Sodium Chloride
    H2SO4: Sulfuric Acid
    Na2SO4: Sodium Sulfate
    HCl: Hydrochloric Acid

    In theory I am pretty sure this is the eqn.

    For your question H2Cl is not possible because of the electron configuration. However, H2Cl+ may be possible, if so, I have never heard of it or seen it.


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  4. #3  
    Forum Bachelors Degree The P-manator's Avatar
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    http://en.wikipedia.org/wiki/Sodium_bisulfate

    After more research I found this. It shows the formula that I think I did. I am debating wether I made Na2SO4 or NaHSO4. How could I tell?
    Pierre

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  5. #4  
    Forum Ph.D.
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    perhaps try liberate the hydrogen, and test for it (the pop) and if no pop, then no H,

    but that won't work - silly , damien, because you got no control, so if no pop, you can't say theres no H.

    more usless info sorry ,

    try it though ..?

    you could, *im stabbing in the dark here* see, if its Na2SO4 then add BaCl2, which whould form a white cloudyness, (if im rembering this correct), and if its NaHSO4 then the H would either:

    mess up the reaction? or
    BE liberitated?

    now agian.. its shaky, im not sure if im making sense.
    Stumble on through life.
    Feel free to correct any false information, which unknown to me, may be included in my posts. (also - let this be a disclaimer)
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  6. #5  
    Forum Bachelors Degree The P-manator's Avatar
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    Well I worked it out: I found in my research that under normal conditions it would form Na2SO4, not NaHSO4. SO ther we go, yupla-boom, hooray, end of research, problem solved.
    Pierre

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