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Thread: Pi Bonding (p-d) Orbitals

  1. #1 Pi Bonding (p-d) Orbitals 
    Forum Freshman
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    Oct 2008
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    Hi everyone,

    I have something that I don't understand, and forgive me for not drawing you a Lewis structure and the VSPER model. I don't think I can on the forum. In the anion SO4-2, there are 4 Sigma bonds, 2 of which are (sp3-sp3) and two that are (sp3-sp2) hybridization, and two pi bonds. I don't understand the pi bond (d-p). How is an electron jumping to a d orbital, and how can I determine when this happens. I understand the Sp3 and Sp2 through VSPER, but am totally lost on the (p-d) bonds. Some insight on the P orbital would be helpful too.. There are 5 resonance structures , and I think this would apply to all 5

    Thanks for all your help.

    Mikie


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  3. #2  
    Forum Freshman
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    Oct 2008
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    Welp, got the answer to my question, and correct me if i'm worng here. Sulfur is in column 3 along with Si,P,Cl and Ar on the periodic table. (3)^2 = 9 Where Sulfur is capable of making up to 9 bonds. The remaining electrons in O are in 2 P orbitals y and z, and the S remaining electrons are promoted to the d ordital because the p orbital is filled. As I was told, "They have to go somewhere" Thus, you would have 2 pi bonds with (p-d) orbitals.

    Mikie


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