Does Boron exist in this form B<sub>2</sub> ?
i can't seem to make it work
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Does Boron exist in this form B<sub>2</sub> ?
i can't seem to make it work
? Looking at it at many angles, I don't see how it can be possible.
Way 1:by looking at Boron's electronic configuration:
It needs 5 electrons for 'octet' stability.
only 'gives' 4 electrons for each atom which means a 'no'
Way 2: Look at elements below Boron (Al, Ga, etc), though I don't think its a good way, its still a possibility in the sense that though Boron is a semi-metal, groups tend to have similarities. As those below Boron cannot/does not form anything similar to(where X is any element in the group)
Way 3 (okok, a bit hijacked off wiki here): Look at equations for boron (which in any case would still depend on way 1&2)
In the above reaction, boron does not form aas I would assume by now that it's structure would be similar to how we write for metals, meaning that we write metals as Al, Na, Ca, Rb, etc and not the millions of atoms within the metallic structure.
Hope this answers your question. :-D
The genesis of chemistry can be traced to the widely observed phenomenon of burning that led to metallurgy- the art and science of processing ores to get metals.
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ok, i dont see how this can help OG (organic god) answer his question..Originally Posted by Kyle2008
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