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Thread: Advanced Lemon battery!

  1. #1 Advanced Lemon battery! 
    Forum Freshman
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    Feb 2008
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    14
    Hey!

    Well, we did the lemon battery in school. Re-did it at home. Played with my flashing LED's... And then realized I have to make a documentation on it. (boring part)

    Anyway, the simple one page thing has grown to 5 pages. Teacher better like it. hehe.

    2H+(g) + 2e- → H2 (g) is the cathode half reaction. But I wanted to go a step further and make the molecular reaction. Can someone help me by explaining where the H's come from? What kind of an acid is in lemons? Would this differ from bananas?

    Also in the redox table for a Zinc-Copper cell, you have the following:
    E°cell=E°cathode-E°anode
    =0.34-(-0.76)
    =1.1V @ Standard conditions.

    In this one you still use copper, but hydrogen is being reduced. Does that mean you have to take it for Hydrogen or copper? Would it then be:
    E°cell=E°cathode-E°anode
    =0.00-(-0.76)
    =0.76V @ Standard conditions.

    Thanks.


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  3. #2  
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    Feb 2008
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    Hey,

    Ok, i been doing some research. The acid is citric acid. The Cu is still the cathode. But instead its not really part of the reaction in some way. I'm guessing thou that the Cu might be eaten away the acid maybe?

    All I know is that it is the Cathode. So the volts would be 1.1.

    Next, I did research on citric acid. It has 4 OH groups, therefor it is able to release 4H's right?

    Is this right? Should the copper also come in somewhere?

    I'm trying to find a redox table with citric acid on, seeing that the one in my book doesn't have it...

    Thanks.


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  4. #3  
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    Feb 2008
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    ok. I know this isnt right. But maybe it gives someone an idea to helo me.

    Well I have been playing around with the exuations. Got out as something like this.



    Now the last bit I wasn't sure of. So I just tried to make something of it.



    Dont know if you evin get something like that.

    Anyway. Please guys. I seriously need this. Its due for tomorrow.

    Any ideas yet?
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  5. #4  
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    Join Date
    Feb 2008
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    14
    Hey.

    Is my question really stupid? Really hard? Under the wrong heading?

    My project is already in so I can't get marks on it anymore. If that bothered anyone. But I still need to know.

    Im as curious as hell and I don't know where to find out.

    Please help me out.

    Thanks.

    Dark_Fire
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