Hi,
I have to make up a 0.5N solution of HNO3 (69%). I have attempted to do the calculation but am not confident if it is correct. Please see below:
no. moles = cv/1000
c = 0.5N v = 100ml
so no.moles = 0.5 x 100/ 1000 = 0.05 moles
mass = 0.05moles/63 = 3.15g
HN03 (69%) = 2.17g
Therefore 2.17g of HNO3 (69%) in 100ml water = 0.5N
Is this correct? (As someone else seems to have got 4.56g as the answer and I dont know where they obtained this from)
Thank you very much for any help.