As per Meiosis 1 defintion, this phase reduces 2n to (n and n)
If I have two 2*23 chromosomes-
x1, x2, x3,.....x23
y1, x2 ,y3....y23
I realise at end of Telophase 1 following 92 chromosomes will exist ( each replicated twice)
x1 x1 x2 x2 x3 x3 x4 x4.....x23 x23
y1 y1 y2 y2 y3 y3 y4 y4.... y23 y23
What is the end results of meiosis1:
Will two cells have
cell 1 - x1x1, y2,y2. x3x3. .........x23x23 (46 pairs - numbers 1-23 present. Either x or y will have number 1-23)
cell 2 - y1y1, x2,x2. y3y3. .........y23y23 (46 pairs - numbers 1-23 present. Based on result 1, Either x or y will have number 1-23)
Is my understanding correct?