Thread: True age in seconds

A question for a project where I am working on.

When I was born as an individual on july the first 1983 at 01h, 01min, 01sec PM. how long in seconds do I walk on the face of the earth at a given moment ‘now‘; for example june the second, 01h, 01min, 01sec PM?

What is the best definition to use for a year (Julian, Tropical, Anomalistic)?

Or if the length of a year is changing over time, how to apply these astronomical algorithms ( http://www.geoastro.de/elevaz/basics/meeus.htm ) if your born in 1983?


Marcel

Real fast on the calculator, hope its right

24 years = 24yrs x 365days x 24hrs x 60 mins x 60 secs =758,864,000 secs

6 leap years in that stretch so add 6 days = 6 days x 24hrs x 60 mins x 60 secs = 518,000 secs

Toatal....757,382,400 secs

This is not time spent actually walking but time spent living outside the womb. Is that what you were asking?

You forgot the leap seconds that are added in occasionally.

I thought you were kidding about leap seconds, then wikipedia told me you weren't lying. It really is surprising the things that I have never heard of.

Originally Posted by Ophiolite

You forgot the leap seconds that are added in occasionally.

I knew it sounded too easy

Add 1 sec/500 days (approx) = 17.5 secs using original data

But....

That's the measurement of an Earth day. The time spent going around the Sun would still be 365 1/4 days.

The leap second is about the Earth's rotation slowing down so how would that affect the time for Earth's revolutions around the Sun? What am I missing here?

Aren't we just resetting a clock for length of a day, regaining a lost second over 500 days, when we talk about a leap second? Just a correction but nothing is really lost or gained. I don't think it would affect the length of a year in seconds unless the Earth's revolutions around the Sun are slowing down.